I'm not sure but I think it's 5
9514 1404 393
Answer:
(b) 112.2 ft
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
For the given geometry, this becomes ...
tan(65°) = (height above eye level)/(50 ft)
Then we have ...
(height above eye level) = (50 ft)tan(65°) = 107.2 ft
Adding the height of eye level will give us the height of the building.
building height = (eye level height) + (height above eye level)
building height = (5 ft) + (107.2 ft)
building height = 112.2 ft
What grade is this? can you maybe break it down
