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abruzzese [7]
3 years ago
10

Michael estimated his mass as 8 kilograms. Is his estimate reasonable? Justify your answer.

Mathematics
1 answer:
Gennadij [26K]3 years ago
8 0

Answer:  The answer is Yes.


Step-by-step explanation:  Given that Michael estimated his mass and found it to be 8 kilograms. It may sound awkward to us, but its true. Because when we measure our weight by the weight machine it gives us the product of our actual mass and the acceleration due to gravity.

From second law of motion, we have

Weight = mass × acceleration due to gravity.

That is, W = m × 9.8 m/sec².

The unit of mass is kilogram and 1 kg m/sec² = 1 Newton. Therefore, the unit of the weight we generally measure is Newton (N), not kilogram. Here is what we make mistake usually.

Thus, if Michael' mass is 8 kg, then his weight will be

W = 8 × 9.8 kg m/sec² = 78.4 N, which is normal weight of a person.

Thus, his estimation is perfectly OK.


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Step-by-step explanation:

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5 0
3 years ago
Solve for x: 3/3x + 1/x+4 = 10/7x
Mekhanik [1.2K]
Given,

3/3x + 1/(x + 4) = 10/7x

1/x + 1/(x+4) = 10/7x

Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x

Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,

{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

(x + 4 + 1x) / (x(x + 4)) = 10/7x

(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled. 

∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4

∴x = 3



8 0
3 years ago
8. The book fair had a sale where 6 books were $20.46. If you wanted to buy 7 books, how much money would you need?
Margaret [11]

Answer:

$23.87

Step-by-step explanation:

should be around there

6 0
3 years ago
Read 2 more answers
PLEASE, PLEASE, PLEASE HELP ME!!!! I NEED THE ANSWER IN ONE HOUR!!! Ben has 57 toys. 15 of them are new, 9 are his favorite ones
storchak [24]
So.... there are a total of 57 toys, which the new and favorites ones are not going to be sold.

The equation would ultimately go into 57 - (15+9+2), which would equal to 31. Ultimately, he sells 31 toys and have 26 left over.

in short, subtracting 57 with the sum of 15+9+2 would equal to 31 toys which means that he sells the 31 toys.
3 0
3 years ago
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