All categories

3 years ago

Write the equation in slope-intercept form of the line that has a slope of -7/8 and contains the point (-4, 9).

Mathematics

1 answer:

lubasha [3.4K]3 years ago

6 0

Answer:

The equation of the line is y = -7/8x + 11/2

Step-by-step explanation:

Since we have the slope and a point to start, we can use point-slope form to find the equation.

y - y1 = m(x - x1)

Use the slope for m and the point at (x1, y1). Then solve for y.

y - 9 = -7/8(x + 4)

y - 9 = -7/8x - 7/2

y = -7/8x + 11/2

You might be interested in

Please help me. I can't figure out how to get an equation

Eddi Din [679]

A printer shop purchases a new printer fro $25,000
the equipment depreciates at a rate of 5% each year
the relationship between the value of the printer, y, and the year number, x can represented by the equation y=25,000*0.95^x
year 1: $23,750
year 2: $22,562.50
year 3: $21,434.38

8 0

3 years ago

What is the measure of Angle R?

Ostrovityanka [42]

Answer:

60°.

Step-by-step explanation:

6 0

2 years ago

If you get this right i will give a brainlest

VARVARA [1.3K]

Answer:

Step-by-step explanation:

Because the rest are wrong. It is just asking you to compare the numbers. choice B says that Group 1/A needs 6 more lessons than Group 12/B

4 0

2 years ago

Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f

Korvikt [17]

If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
$\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C$

So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23$

5 0

2 years ago

I need help with this question please

Novay_Z [31]

I think the answer is 80 because I’m point 2 it’s is 40 and in point 3 is 60 and in point 5 is 100 so I am guessing each goes by 20 so what is between 60 and 100 if you can’t by 20s would be 80 I don’t know if I am correct tho

4 0

3 years ago