Answer:
phase difference = π / 2
constructive interference
Explanation:
Given data
wavelength = 420 nm
1st beam = 105 nm
path difference = 105 nm
to find out
phase difference and interference pattern of the two beams
solution
we use here equation of phase difference that is
phase difference = 2π / wavelength × Δx
put here value
phase difference = 2π / 420 × 105
phase difference = π / 2
and
we know that here path difference Δx is the integral multiple of the wavelength so it will be constructive interference
Δx is wavelength / 4
The Law of the Conservation of Energy is stating that the total mechanical energy is always conserved or in simpler terms, not used or saved.
Answer:
im pretty sure its c the third answer i got that one right
Explanation:
your welcome :)
Energy of the waves are redistributed to form a resultant wave with amplitude given by the summation of individual wave's amplitude.
<span>If the two waves are of same frequency, speed and amplitude and travelling in opposite direction den stationary waves are form.</span>
Answer:
Explanation:
For this exercise we must use the principle of conservation of energy
starting point. The proton very far from the nucleus
Em₀ = K = ½ m v²
final point. The point where the proton is stopped (v = 0)
Em_f = U = q V
where the potential is
V = k Ze / r²
Let us consider that all the charge of the nucleus is in the center, therefore r is the distance from this point to the proton that is approaching
Energy is conserved
Em₀ = Em_f
½ m v² = e (
)
with this expression we can find the closest approach distance (r)
