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zloy xaker [14]

4 years ago

8

A robotic arm lifts a stack of cafeteria trays weighing 62 newtons (N). It moves the trays 2 meters (m). How much work has the r

obotic arm performed?

1 answer:

tigry1 [53]4 years ago

7 0

work done = force * distance

work = 62 * 2 = 124 j

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A 5 kg projectile is fired at an angle of 25o above the horizontal. Its initial velocity is 200 m/s and just before it hits the

lina2011 [118]

Answer:

The change in the mechanical energy of the projectile is 43,750 J

Explanation:

Given;

mass of the projectile, m = 5 kg

initial velocity of the projectile, u = 200 m/s

final velocity of the projectile, v = 150 m/s

The change in mechanical energy is calculated from the principle of conservation of energy;

ΔP.E = ΔK.E

The change in potential energy is zero (0)

0 = ΔK.E

ΔK.E = K.E₁ - K.E₂

ΔK.E = ¹/₂mu² - ¹/₂mv²

ΔK.E = ¹/₂m(u² - v²)

ΔK.E = ¹/₂ x 5(200² - 150²)

ΔK.E = 43,750 J

Therefore, the change in the mechanical energy of the projectile is 43,750 J

4 0

3 years ago

You are standing next to a table and looking down on a record player sitting on the table. Take the spindle (axis of rotation) t

VLD [36.1K]

Answer:

a) the rotational speed of the clay is 3.45 rad/s

b) the value of A in the equation of motion is 0.15 m

c) the value of ϕi is 90° or π/2 rad.

Explanation:

Given that;

Revolution per minute rpm = 33( 1/3) = 100/3

The frequency f = 100 / 3(60) = 0.55 Hz

a)

Rotational speed W = 2πf

we substitute

W = 2π × 0.55

W = 3.45 rad/s

Therefore, the rotational speed of the clay is 3.45 rad/s

b)

given equation; y(t)=Asin(ωt+ϕi)

given that radius = 0.15 m

y(t)=(0.2)sin(ωt+ϕi)

Therefore, the value of A in the equation of motion is 0.15 m

c)

since y(t) has the maximum value at t =0

so at t=0

y(0) = (0.15)sin(ω(0)+ϕi)

= 0.15sin(ϕi)

this will give maximum value when ϕi = 90°

so

y(0) = (0.15)sin(ω(0)+ϕi)

= 0.15sin(90°)

= 0.15

hence, the value of ϕi is 90° or π/2 rad.

7 0

3 years ago

What information do you need to describe an objects location

Ainat [17]

The information you need to describe an objects location is a map,books,or GPS,which is the same thing as a map!?! Right?!?

4 0

4 years ago

What is the speed of an object that moves 100 km in 45 minutes?

lana [24]

133 kilometers per hour

5 0

4 years ago

A regulation soccer field for international play is a rectangle with a length between 100 m and a width between 64 m and 75 m. W

tatyana61 [14]

Answer:

The smallest and largest areas could be 6400 m and 7500 m, respectively.

Explanation:

The area of a rectangle is given by:

$A = l*w$

Where:

l: is the length = 100 m

w: is the width

We can calculate the smallest area with the lower value of the width.

$A_{s} = 100 m*64 m = 6400 m^{2}$

And the largest area is:

$A_{l} = 100 m*75 m = 7500 m^{2}$

Therefore, the smallest and largest areas could be 6400 m and 7500 m, respectively.

I hope it helps you!

5 0

3 years ago

Read 2 more answers