Answer:
The probability that 10 adults selected at random from the town all have health insurance is 0.01153.
Step-by-step explanation:
Consider the provided information.
One town, 64% of adults have health insurance.
Let p = 64% = 0.64
Therefore, q=1-0.64=0.36
We need to find the probability that 10 adults selected at random from the town all have health insurance
Use the formula: 
Here, the value of r is 10.
Substitute the respective values in the above formula.
Hence, the probability that 10 adults selected at random from the town all have health insurance is 0.01153.
Answer:
2045
Step-by-step explanation:
-34×12(-5)+5
-405(-5)+5
2040+5
2045 is the answer
Answer:
a= 11
Step-by-step explanation:
9a+ 6°+75° =180° (straight angle, they are called supplementary angles. so sum is equal to 180°
9a +81 = 180
9a= 99
a= 11
To find the answer you need to identify what x is.
To find the x first you need to make the equation 6x+11=29.
You then subtract 11 from each side which cancels out the 11 and makes the 29 18.
You then divide the entire equation by 6 to get the answer x=3.
You then input x for the CN line equation.
4(3)+1
Thus, your answer should be 13 (D)
Answer:
The observed value of the chi-square statistic is 34.71
Step-by-step explanation:
Given the data in the question';
Calculate the observed value of the chi-square statistic
The chi-square statistic will be;
∑
[ ( O - E)² / E ]
here O is observed frequency of th class
E is expected frequency of th class
= 1, 2 which denote the class of food experts who guess correctly and who didn't guess correctly
so
∈ = n × probability of not guessing correctly = 168 × 2/3 = 112
∈1 = n × probability of guessing correctly 168 × 1/3 = 56
so
∑[ ( O - E)² / E ] = [ ( 92 - 56)² / 56 ] + [ ( 76 - 112)² / 112 ]
= 1296/56 + 1296/112
= 23.14 + 11.57
= 34.71
Therefore, the observed value of the chi-square statistic is 34.71
