Your equation would be:
D. y = 10x + 6
Answer:
1. 
2. ![x=\pm7i[tex]3.[tex]\pm 12x =a](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fp%3E%3Cp%3E3.%5Btex%5D%5Cpm%2012x%20%3Da)
4. 22
Step-by-step explanation:
1. 



2. 


![x=\pm7i[tex]3. Area of square = [tex]a^{2}](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E3.%20Area%20of%20square%20%3D%20%5Btex%5Da%5E%7B2%7D)
Where a is the side
We are given an area o square = 
So, 


4. We are given that the solution of quadratic equation -9 and 9
So, equation becomes:


So, in the given equation 
z should be the number from which if we subtract 103 so we get 81
Substitute z = 22



Thus the value of z is 22
Answer:
x = 46°
Step-by-step explanation:
the opposite angles of a cyclic quadrilateral are supplementary, sum to 180° , then
x + 134° = 180° ( subtract 134° from both sides )
x = 46°
9514 1404 393
Answer:
-203.1875
Step-by-step explanation:
The ends of the interval are ...
(-4, g(-4)) = (-4, 1023 15/16)
(1, g(1)) = (1, 8)
The average rate of change is the slope of the line between these two points:
m = (y2 -y1)/(x2 -x1)
m = (8 -(1023 15/16))/(1 -(-4)) = (-1015 15/16)/5 = -203 3/16
The average rate of change on the interval is -203 3/16.
Slope formula: y2-y1/x-x1
We can use the given points to solve.
3-(-3)/7-5
6/2
3
Best of Luck!