Given:
initial angular speed,
= 21.5 rad/s
final angular speed,
= 28.0 rad/s
time, t = 3.50 s
Solution:
Angular acceleration can be defined as the time rate of change of angular velocity and is given by:
![\alpha = \frac{\omega_{f} - \omega _{i}}{t}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B%5Comega_%7Bf%7D%20-%20%5Comega%20_%7Bi%7D%7D%7Bt%7D)
Now, putting the given values in the above formula:
![\alpha = \frac{28.0 - 21.5}{3.50}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B28.0%20-%2021.5%7D%7B3.50%7D)
![\alpha = 1.86 m/s^{2}](https://tex.z-dn.net/?f=%5Calpha%20%3D%201.86%20m%2Fs%5E%7B2%7D)
Therefore, angular acceleration is:
![\alpha = 1.86 m/s^{2}](https://tex.z-dn.net/?f=%5Calpha%20%3D%201.86%20m%2Fs%5E%7B2%7D)
Answer:
to have an accurate measure
Explanation:
Here are the ones that I know about
and can think of just now:
-- wind
-- solar
-- nuclear
-- tidal
-- hydro
-- geothermal
-- biomass
Electromagnetic waves<span> transfer energy without going through a medium. ... Sometimes, a </span>transverse wave<span> and a </span>longitudinal wave can combine to form<span>another </span>kind<span> of </span>wave<span> called a surface </span>wave<span>. </span>Transverse Waves<span>. </span>Waves<span> in which the particles vibrate in an up-and-down motion
</span>