Answer:
Explanation:
Let the equal charges be Q .
Force between charges = k Q² / R where R is distance between charges , k = 9 x 10⁹.
Putting the charges
Force F = 9 x 10⁹ x Q² /( .72 x 10⁻²)²
= 17.36 x 10¹³ Q² N
This force equals weight so
17.36 x 10¹³ Q² = 15.7 x 10⁻³
Q² = .90 x 10⁻¹⁶
Q = .95 x 10⁻⁸
= 9.5 x 10⁻⁹
= 9.5 nC.
It turns out that the star in question belongs to the K5V star class. Thus, the surface temperature of this must be between 5200 K and 3700 K. It has a surface temperature of 6200 K to 5200 K and is a G2V class star, commonly known as Bernard's star. In other words, the star in question has a colder surface than HIP 87937. This is further explained below.
<h3>What is surface temperature?</h3>
Generally, The temperature at a surface is referred to as the surface temperature. In particular, it may refer to the surface air temperature, which is the temperature of the air that is relatively close to the earth's surface.
In conclusion, The star in question is of the K5V type. Therefore, the temperature of the surface of this must be somewhere between 5200 and 3700 kelvin. The star with the designation HIP 87937, often known as Bernard's star, is of the G2V type. Stars of this type have a surface temperature that falls anywhere between 6200 and 5200 degrees Celsius. Therefore, it should come as no surprise that the surface temperature of the given star is lower than that of HIP 87937.
Read more about surface temperature
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Because it's heavier. I think
Hypnosis may not be completely reliable in most cases.
