Question

A rigid steel container with a volume of 100.0 liters is filled with nitrogen gas to a pressure of 30 atmospheres at 295 kelvins. how many moles of nitrogen gas does the cylinder contain

Answer 1

Data:

P (pressure) = 30 atm
V (volume) = 100.0 L
T (temperature) = 295 K
n (number of mols) = ?
R (Gas constant) = 0.082 (atm*L/mol*K)

Formula: 

$p*V = n*R*T$

Solving:
$p*V = n*R*T$
$30*100.0 = n*0.082*295$
$3000 = 24.19n$
$24.19n = 3000$
$n = \frac{3000}{24.19}$
$\boxed{\boxed{n \approx 124.01\:mols}}\end{array}}\qquad\quad\checkmark$