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VladimirAG [237]
3 years ago
10

Can I please know What are the answers for #s 1,2,3,4 ?

Chemistry
2 answers:
dimulka [17.4K]3 years ago
8 0
1 wavelength, 2 crest, 3 trough, 4 wave height <3
vaieri [72.5K]3 years ago
4 0
I agree with Cora on these questions.
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Calculate the energy in joules and calories required to heat 50.0g silver from 106c to 255c. ​
Ganezh [65]

Answer:

Explanation:

use this fromula

q = m c ∆t

m  is mass of silver =50 g

∆t is difference in temperature= 255-106=149

C=  specific heat fo silver ( should be mentioned in your question )

5 0
2 years ago
Beryllium oxide, Beo, is an electrical insulator. How
egoroff_w [7]

Answer:

There are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.

Explanation:

We can calculate the number of moles (η) of BeO as follows:

\eta = \frac{m}{M}

Where:

m: is the mass = 250 g

M: is the molar mass = 25.0116 g/mol

Hence, the number of moles is:

\eta = \frac{250 g}{25.0116 g/mol} = 10.0 moles

Therefore, there are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.  

I hope it helps you!

3 0
3 years ago
When ironing clothes the primary method of heat transfers conduction convection insulation or radiation
postnew [5]
Convection insulation
7 0
2 years ago
Which quantum number distinguishes the different shapes of the orbitals?
UkoKoshka [18]
The four quantum numbers are:
principle quantum number: this number describes the energy of orbitals. It describes the most probable distance between the electron and the nucleus.
angular quantum number: this number describes the shape of orbitals, and thus, describes the angular distribution.
magnetic quantum number: this number describes the number of orbitals and how they are oriented within the subshell
spin quantum number: this number determines the direction of the spin of the electron.

Based on the above, the quantum number that distinguishes the different shapes of the orbitals is the angular quantum number
7 0
3 years ago
Using molecular orbital theory, explain why the removal of one electron in O2 strengthens bonding, while the removal of one elec
Nuetrik [128]
First you have a knowledge of bond order which is
 B.O=(no. of electrons in bonding orbital - no. of electrons in non-bonding orbital)÷2  
Note:
bond strength is directly proportional to bond order.
For oxygen:
B.O=(6-2)/2= 2; after the removal of two electrons(removal occur from non-bonding orbital)
B.O=(6-0)/2= 3 (As B.O increased bond strength increased)
For Nitrogen:
B.O=(6-0)/2= 3; after the removal of two electrons(removal occur from bonding orbital)
B.O=(4-0)/2= 2 (As B.O decreased bond strength decreased)

6 0
3 years ago
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