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timofeeve [1]
3 years ago
10

What is the input value for the following function if the output value is 5?

Mathematics
1 answer:
Minchanka [31]3 years ago
4 0
The answer is 25, leave a like (:
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Can someone please help me with this! I'll do my best to give a lot of points for it!
Triss [41]
1. By combining like terms
2. Same variable = same term, so you can combine them
3. Because 2y - y = 1y , and 1y is the same as y because a y is one y (obviously)
4. 1/2 + 1/2 = 1. A half an x and a half an x makes one whole x, therefore, x
5. No. You solve them like you would a normal equation with like terms. So it would be 3z^2

Hopefully these are right, I’m a bit rusty!
6. 4x
7. 3y
8. y - 4.5
9. 3.5x + 2
10. 4y + 2
11. 7x
12. 2.2w - 0.5
13. 23b + 6.6
14. 3.75x + 1.5
15. 0.8x + 2.1
Good luck, I hope this helped
8 0
3 years ago
What’s 5x[(26-4)-(4+6)
seropon [69]

Answer:

The Answer is: The factors reduce to 60x.

Step-by-step explanation:

First the parenthesis, then the bracket, then the multiplication:

5x[(26 - 4) - (4 + 6)]

5x[22 - 10]

5x[12]

60x

Hope this helps! Have an Awesome Day!! :-)

8 0
3 years ago
Read 2 more answers
what is the missing side in a right triangle if one leg measures 5 cm and the longest side measures 13 cm
Alika [10]

Answer:

<u>The missing side is 12 cm length</u>

Step-by-step explanation:

1. Let's review the information given to us to solve the case correctly:

Length of the longest side= 13 cm

Length of one leg = 5 cm

2. Using the Pythagorean theorem for finding the length of the second leg, because this is a right triangle:

2nd leg² = Length of the longest side ² - Length of one leg²

2nd leg² = 13 ²  - 5 ²

2nd leg² = 169  -25

2nd leg² = 144

2nd leg = √144

2nd leg = 12 cm

<u>The missing side is 12 cm length</u>

3 0
3 years ago
What is the value of y?
Ratling [72]
The answer to the question I believe is 3.
7 0
3 years ago
Which expressions are equivalent to 2 (three-fourths x + 7) minus 3 (one-half x minus 5)? Check all that apply.
Mariulka [41]

Answer:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

Step-by-step explanation:

The original expression given in the text is

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)  (1)

And we want to check to what other expressions is equivalent. First of all, we solve it by writing explicitely each term:

\frac{3}{2}x+14-\frac{3}{2}x+15 (2)

Let's verify each of the other expressions separately. For the first one:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

We see that this is equivalent to expression (1), since the first half is identical, while in the second one, the combination "+-" can be simply written as "-", so we get

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)

Which is equivalent to (1).

For the 2nd one:

2(\frac{3}{4}x)+2(7)+3(\frac{1}{2}x)+3(-5)

This is not equivalent. In fact, here we have applied the distributive property to each term: however, the 3rd and 4th term are not correct, because the (3) must be negative (-3), as in the original expression.

If we write it explicitely in fact, we get

\frac{3}{2}x+14+\frac{3}{2}x-15

Which is different from (2).

For the 3rd one:

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

This one is equivalent. In fact, here we have applied the distributive property correctly. By solvign each term we get:

\frac{3}{2}x+14-\frac{3}{2}x+15

8 0
4 years ago
Read 2 more answers
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