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Elena L [17]
3 years ago
7

A mass of 14 kg is accelerated at 2m/s2 for a distance of 5 meters. How much energy is required?

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
3 0
Force = mass * acceleration

= 14 * 2 = 28N

Work done (energy) = Force * distance

= 28 * 5 = 140J
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2 years ago
The equation for photon energy, E , is
Sidana [21]

The wavelength of a photon that has an energy of E = 3.69×10−19 J is 5.42 x 10⁻⁷ m.

<h3>What do you mean by wavelength?</h3>

The space between corresponding points (adjacent crests) in adjacent cycles is known as the wavelength () of a waveform signal that is sent in space or down a wire.

The wavelength can be calculated by the given formula

E = hc/λ

Where,  E is energy = 3.65 x 10⁻¹⁹ J

h is plank's constant = 6.626 x 10⁻³⁴ J.sec

c is speed of light = 2.9 × 10⁸ m/s

Putting the values in the formula

λ = (6.626 x 10⁻³⁴)(2.9 × 10⁸) / (3.65 x 10⁻¹⁹) = 5.42 x 10⁻⁷ m.

Thus, the wavelength, λ is 5.42 x 10⁻⁷ m.

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4 0
2 years ago
Write the structure of butanoate ion.
drek231 [11]

Answer:

Explanation:

Molecular FormulaC4H7O2

Average mass87.098 Da

Monoisotopic mass87.045151 Da

4 0
2 years ago
14. What is the pH of a 0.24 M solution of sodium propionate, NaC3H502, at 25°C? (For
Murrr4er [49]

Answer:

9.1

Explanation:

Step 1: Calculate the basic dissociation constant of propionate ion (Kb)

Sodium propionate is a strong electrolyte that dissociates according to the following equation.

NaC₃H₅O₂ ⇒ Na⁺ + C₃H₅O₂⁻

Propionate is the conjugate base of propionic acid according to the following equation.

C₃H₅O₂⁻ + H₂O ⇄ HC₃H₅O₂ + OH⁻

We can calculate Kb for propionate using the following expression.

Ka × Kb = Kw

Kb = Kw/Ka = 1.0 × 10⁻¹⁴/1.3 × 10⁻⁵ = 7.7 × 10⁻¹⁰

Step 2: Calculate the concentration of OH⁻

The concentration of the base (Cb) is 0.24 M. We can calculate [OH⁻] using the following expression.

[OH⁻] = √(Kb × Cb) = √(7.7 × 10⁻¹⁰ × 0.24) = 1.4 × 10⁻⁵ M

Step 3: Calculate the concentration of H⁺

We will use the following expression.

Kw = [H⁺] × [OH⁻]

[H⁺] = Kw/[OH⁻] = 1.0 × 10⁻¹⁴/1.4 × 10⁻⁵ = 7.1 × 10⁻¹⁰ M

Step 4: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺] = -log 7.1 × 10⁻¹⁰ = 9.1

5 0
3 years ago
Calculate the mass of water produced when 2.06 g of butane reacts with excess oxygen.
dem82 [27]
2C4H10 + 13O2 = 8CO2 + 10H2O

1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10

2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O

3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O
8 0
3 years ago
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