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mina [271]
3 years ago
9

A scientist finds that one volume of an unknown gas X combines with two volumes of another gas Y to form two volumes of a new ga

s with a formula XY2. Are any of the gases diatomic?
Chemistry
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

Gas X

Explanation:

The given reaction can be written in the form of chemical equation as shown below as:

X+2Y\rightarrow 2XY_2

According to law of conservation of mass, the moles of each substance in the reaction must be equal on both reactant and product side.

Also, the question asks for the gas which is diatomic. XY_2 cannot be diatomic as the formula contains 3 atoms.

Between gas X and gas Y , <u>X has to be diatomic for the reaction to balance </u>as:

X_2+2Y\rightarrow 2XY_2

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Explain what would happen if an electron and a proton were brought near each other and then released. why would this happen?
Leni [432]
They would repel one another because they they have opposing charges
3 0
3 years ago
If Kc = 4.0×10−2 for PCl3(g)+Cl2(g)⇌PCl5(g) at 520 K , what is the value of Kp for this reaction at this temperature?
Flauer [41]

Here we have to get the K_{p} of the reaction at 520 K temperature.

The K_{p} of the reaction is 1.705 atm

We know the relation between K_{p} and K_{c} is K_{p}=K_{c}(RT)^{N}, where  K_{p} = The equilibrium constant of the reaction in terms of partial pressure, K_{c}  = The equilibrium constant of the reaction in terms of concentration and N = number of moles of gaseous products - Number of moles of gaseous reactants.

Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅

Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole

The given value of  K_{c} is 4.0×10⁻²

The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.

On plugging the values in the equation we get,

K_{p} = 4.0 X 10^{-2}(0.082X520)^{1}

Or, K_{p} = 1.705 atm

Thus, the K_{p} of the reaction is 1.705 atm

7 0
3 years ago
Simple question plzz help
PSYCHO15rus [73]

Answer:

a  

Explanation:

3 0
2 years ago
Read 2 more answers
It was calculated that 4.3mL of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M Mg(OH)2. Show evidence 2 HCl(aq) + Mg(OH)2
Lapatulllka [165]

Answer:

See explanation.

Explanation:

Hello,

In this case, for the described chemical reaction:

2 HCl(aq) + Mg(OH)2(aq) → MgCl2(aq) + 2 H2O(l)

We can notice there is a 2:1 molar ratio between the moles of hydrochloric acid and magnesium hydroxide, therefore, at the equivalence point:

n_{HCl}=2*n_{Mg(OH)_2}

And in terms of volumes and concentrations we verify:

V_{HCl}M_{HCl}=2*V_{Mg(OH)_2}M_{Mg(OH)_2}

So we use the given data to proof it:

4.3mL*0.417M=2*11.9mL*0.151M\\1.793=3.594

Therefore, we can conclude the data is wrong by means of the 2:1 mole ratio that for sure was not taken into account. This is also supported by the fact that normalities are actually the same, but the nomality of magnesium hydroxide is the half of the hydrochloric acid normality since the acid is monoprotic and the base has two hydroxyl ions.

Best regards.

4 0
2 years ago
What measurements should you use for large amounts of energy transfer
tatuchka [14]
You should use the joules (J) unit of measurement.
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2 years ago
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