Answer: Mass of
required to form 930 kg of iron is 1328 kg
Explanation:
To calculate the number of moles, we use the equation:
.....(1)
For iron:
Given mass of iron = 930 kg = 930000 g (1kg=1000g)
Molar mass of iron = 56 g/mol
Putting values in equation 1, we get:

The chemical equation for the production of iron follows:

By Stoichiometry of the reaction:
2 moles of iron are produced by = 1 mole of 
So, 16607 moles of iron will be produced by =
of 
Now, calculating the mass of
from equation 1, we get:
Mass of
= 
Thus mass of
required to form 930 kg of iron is 1328 kg