SOMEONE PLEASE HELP ME
2 answers:
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Answer: a) (0.755, 0.925)
Step-by-step explanation:
Let p be the population proportion of 8th graders are involved with some type of after school activity.
As per given , we have
n= 100
sample proportion:
Significance level :
Critical z-value : (using z-value table)
Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-
i.e.
i.e.
i.e.
Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)
Answer:
SinL = 7/25
CosL = 24/25
TanL = 7/24
Step-by-step explanation:
Find the diagram attached.
Using SOH CAH TOA in trigonometry identity to find the sinL, cosL and TanL
Note that the hypotenuse is the longest side = 25
The opposite will be the side facing the acute angle L
Opposite = 7
Adjacent = 24
For SinL
sinL = Opposite/Hypotenuse {SOH}
SinL = 7/25
For cosL:
CosL = Adjacent/Hypotenuse{CAH}
CosL = 24/25
For tanL:
TanL = Opposite/Adjacent {TOA}
TanL = 7/24
