B. When the sun and the moon are aligned, their combined gravitational force attracts the water, causing super high tides on one side of the planet, and super low tides on the opposite side.
Answer:
(a) The work done is 0.05 J
(b) The force will stretch the spring by 3.8 cm
Explanation:
Given;
work done in stretching the spring from 30 cm to 45 cm, W = 3 J
extension of the spring, x = 45 cm - 30 cm = 15 cm = 0.15 m
The work done is given by;
W = ¹/₂kx²
where;
k is the force constant of the spring
k = 2W / x²
k = (2 x 3) / (0.15)²
k = 266.67 N/m
(a) the extension of the spring, x = 37 cm - 35 cm = 2 cm = 0.02 m
work done is given by;
W = ¹/₂kx²
W = ¹/₂ (266.67)(0.02)²
W = 0.05 J
(b) force = 10 N
natural length L = 30 cm
F = kx
x = F / k
x = 10 / 266.67
x = 0.0375 m
x = 3.75 cm = 3.8 cm
Thus a force of 10 N will stretch the spring by 3.8 cm
Given :
A jogger runs 5.0 km on a straight trail at an angle of 60° south of west.
To Find :
The southern component of the run rounded to the nearest tenth of a kilometre.
Solution :
We know, southern component is given by :

Here, negative sign indicates south direction.
Therefore, the southern component of the run rounded to the nearest tenth of a kilometre is 4.3 km.
Hence, this is the required solution.