Once broken into parts curved motion can be worked as _______________

An 67-kg jogger is heading due east at a speed of 2.3 m/s. A 70-kg jogger is heading 61 ° north of east at a speed of 1.3 m/s. F

ololo11 [35]

Answer

given,

mass of jogger = 67 kg

speed in east direction = 2.3 m/s

mass of jogger 2 = 70 Kg

speed = 1.3 m/s in 61 ° north of east.

jogger one

$P_1 = m_1 v_1 \hat{i}$

$P_1 = 67 \times 2.3\hat{i}$

$P_1 = 154.1 \hat{i}$

$P_2 = m_2 v_2 \hat{i} +m_2 v_2 \hat{j}$

$P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}$

$P_2 = 70\times 1.3 cos 61^0 \hat{i} +70\times 1.3 sin 61^0\hat{j}$

$P_2 = 44.12\hat{i} +79.59\hat{j}$

now

P = P₁ + P₂

$P = 198.22 \hat{i} +79.59 \hat{j}$

magnitude

$P = \sqrt{198.22^2 + 79.59^2}$

$P =213.60 kg.m/s$

$\theta = tan^{-1}\dfrac{79.59}{198.22}$

$\theta = 21.87$

the angle is $\theta = 21.87$ north of east

7 0

4 years ago

At a processing facility outside of Detroit, a 7.0 kg box of goat cheese, initially at rest, is given a push up a smooth, inclin

Firlakuza [10]

Answer:

d = 5.9 m

Explanation:

During the initial push, there are two forces acting on the box along the ramp: the component of gravity force along the ramp (directed to the bottom of the ramp), and the pushing force (up the ramp).

As we have as a given, the time during which the pushing force is applied, we can use Newton's 2nd Law, expressed in its original form, as follows:

Fnet *Δt = Δp = m* (vf-v₀) (1)

Fnet, in this case, is the difference between Fapp, and the projection of Fg along the ramp, which is equal to Fg times the sinus of the angle of the ramp with respect to the horizontal.

We choose as positive, the direction up the ramp, so we can write the follwing equation:

⇒ Fnet = Fapp - Fg*sin θ = 140 N - (7kg*9.8m/s²*sin 30º) = 140 N - 34.3 N

⇒ Fnet = 105.7 N

Replacing in (1):

105.7 N * 0.5 s = 7 kg* vf (v₀=0, as the box starts from rest)

Solving for vf:

vf = 105.7 N* 0.5 s / 7 kg = 7.6 m/s

When the push ends, the only force remaining along the ramp, is the component of Fg that we have already obtained, that will cause the box to have a deceleration, which we can find out aplying Newton's 2nd Law, as follows:

m*g*sin 30º = m*a

As we have defined as positive direction the one up the ramp, a will be negative (as it is slowing down the box) , and can be calculated as follows:

a = -34.3 N / 7 kg = -4.9 m/s²

As this value is constant, we can use any kinematic equation in order to get the distance traveled, farther the point where it disappeared the influence of the pushing force:

vf² - v₀² = 2*a*d

As we know that finally the box will come momentarily at rest (before falling under the influence of gravity) , we have vf =0:

⇒ -v₀² = 2*a*d

For this part, v₀, is just the value for vf, that we got above:

v₀= 7.6 m/s

⇒ -(7.6)² =2*(-4.9 m/s²)*d

Solving finally for d (the answer we are looking for):

d = (7.6)² (m/s)² / 2*4.9 m/s² = 5.9 m

8 0

3 years ago

#1 “A persons body continuing to move forward even though the car comes to a sudden stop” Which newtons Law Do they pertain? A:

Aloiza [94]

#1 “A persons body continuing to move forward even though the car comes to a sudden stop” Which newtons Law Do they pertain?
A: First Law 

#2 “A fighter Pilot Feels Massive Amounts of forcé when his plane turns sharply” Which Newton Law?
A: First Law.
You were following the Newton's first law and kept your velocity straight until you departed from linear motion when you turn sharply; you are forced to follow the curve. The force that the jet exerts on you is called centripetal force and is suitable for the center of curvature of the forced traveling path.

#3 “ A Paddle wheel boat pushed on water and the water pushes back causing the boat to move” Which Netwons Law?
C: Third Law

3 0

3 years ago

WILL GIVE BRAINLIST

marshall27 [118]

Answer:

The Graph Shows World Disasters.

Answer Pt.2:

As we all can see the tornado's Have the highest ratings of natural disasters, Hurricane's happen the next most, Landslide's happen less often, Wildfires also happen less often whereas Earthquakes nearly never happen, they are very rare to the world.

3 0

2 years ago

Read 2 more answers

One system consists of two like charges (q1 and q2) separated by a distance r. A second system consists of two charges that are

olganol [36]

fyt as per the question the magnitude of two like charges are given as q1 and q2.the separation distance is given as r unit.hence the potential energy is given as- $P.E=+\frac{1}{4\pi\epsilon} \frac{q1*q2}{r^2}$

here the potential energy is positive which means the force between two charges is repulsive.the potential energy is maximum which indirectly denotes that the system is unstable.due to this repulsion the smaller charge may accelerate.

coming to the same charges of opposite nature i.e unlike charges-here the magnitude of charges are same and separation distance is also are,so the potential energy will be given as- $P.E=-\frac{1}{4\pi\epsilon}\frac{q1*q2}{r^2}$

here the potential energy is negative .so the system of two charges are attracted by each other.

4 0

4 years ago

Read 2 more answers

Once broken into parts curved motion can be worked as ________________ problems along both axes.