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frozen [14]
3 years ago
15

uppose that 3 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 45 cm. (a) How much work i

s needed to stretch the spring from 35 cm to 37 cm? (Round your answer to two decimal places.) .02 Incorrect: Your answer is incorrect. J (b) How far beyond its natural length will a force of 10 N keep the spring stretched? (Round your answer one decimal place.)
Physics
1 answer:
Lesechka [4]3 years ago
7 0

Answer:

(a) The work done is 0.05 J

(b) The  force will stretch the spring by 3.8 cm

Explanation:

Given;

work done in stretching the spring from 30 cm to 45 cm, W = 3 J

extension of the spring, x = 45 cm - 30 cm = 15 cm = 0.15 m

The work done is given by;

W = ¹/₂kx²

where;

k is the force constant of the spring

k = 2W / x²

k = (2 x 3) / (0.15)²

k = 266.67 N/m

(a) the extension of the spring, x = 37 cm - 35 cm = 2 cm = 0.02 m

work done is given by;

W = ¹/₂kx²

W = ¹/₂ (266.67)(0.02)²

W = 0.05 J

(b) force = 10 N

natural length L = 30 cm

F = kx

x = F / k

x = 10 / 266.67

x = 0.0375 m

x = 3.75 cm = 3.8 cm

Thus a force of 10 N will stretch the spring by 3.8 cm

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Based on the nature of constructive interference,

none of the wave intersections will produce constructive interference.

<h3>What is constructive interference?</h3>

Constructive interference is interference that occurs when two waves of the same frequency amplitude and wavelength travelling in the same direction are superposed with the resultant effect of reinforcement of both waves to produce a larger wave.

Constructive interference occurs when the path difference between two identical waves at a point is:

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where n = 0, 1, 2, ...

For the various intersections:

  • 1.77 cm crest intersecting with a 0.65 cm crest; n = 1.77/0.65 = 2.7
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