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Alecsey [184]
3 years ago
14

Plzzzzzzz help asappp

Mathematics
2 answers:
alexgriva [62]3 years ago
6 0
I think that it’s 9.9
Romashka [77]3 years ago
3 0
9.9
With right triangles you can use the equation a^2 + b^2 = c^2. Since both a and b are 7, that makes it 7^2 + 7^2 = c^2 and from there 49 + 49 = c^2 and then 98 = c^2. Then go find C, you find the square root of 98 which is 9.899494937 or rounded as 9.9

Keep in mind a^2 + b^2 = c^2 only works for right triangles, it won’t work for any other ones.
You might be interested in
A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.
olga55 [171]
We know that:

(x-a)^2+(y-b)^2=r^2

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}

and all we have to do is solve it for a, b and r.

There will be:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\


From equations (II) and (III) we have:

\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}

and from (I) and (II):

\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}

Now we can easly calculate a and b:

\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}

Finally we calculate r^2:

a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}

And the equation of the circle is:

(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}
7 0
3 years ago
Someone help me with this please
anzhelika [568]

for question 1

Area of Base B =45×25 = 1125 cm²

perimeter of base P = 2(45+25) = 140 cm

Height = 15 cm

Using the formula

Surface area = 2B + Ph

A = 2×1125 + 140×15= 4350 cm²

Voume = Bh = 1125×15= 16875 cm³

For question 2,

Area of base = 7× 5/2= 17.5 cm²

Perimeter of base = (7+7+7) = 21 cm

Surface area = 2B + Ph

Surface area of prism = 2×17.5+ 21×10 = 245cm²

Volume = Bh = 17.5×10 = 175 cm³

6 0
3 years ago
Read 2 more answers
Solve for x
KIM [24]
7.5 ft because
6/30 = .0005 so then x we factor in equals 7.5 for
8 0
3 years ago
Identify the restrictions on the domain of f(x) = quantity x plus 5 over quantity x minus 2. x ≠ 5 x ≠ −5 x ≠ 2 x ≠ −2
horsena [70]

Answer: Third option.

Step-by-step explanation:

By definition, Rational Functions have the following form:

f(x)=\frac{P(x)}{Q(x)}

Where P(x) and Q(x) are polynomials.

The Restrictions of the Domain of Rational Functions are those Real numbers that make the denominator equal to zero, because the division by zero is not defined.

 In this case, you have the following Rational Function:

f(x)=\frac{x+5}{x-2}

The Restrictions of the Domain can be found applying this steps:

- Make the denominator equal to 0:

x-2=0

- Solve for "x":

x=2

Then, the Domain of this function includes all "x" not equal to 2.

Therefore,  the answer is:

x\neq 2

8 0
3 years ago
A cone is cut by a plane parallel to the slant height of the cone. What is the shape of the cross section that is formed?
zimovet [89]
A cross section is a shape formed by cutting an object using a plane. For this case, a cone is sliced parallel to the slant height so the cross section formed would be a plane with a U-like shape. From the image attached, the correct answer is the second option.
8 0
2 years ago
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