<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
Answer:
x < 1/2
Step-by-step explanation:
5(2x + 1) < 10
Divide each side by 5
5/5(2x + 1) < 10/5
2x+1 < 2
Subtract 1 from each side
2x+1-1 < 2-1
2x <1
Divide each side by 2
2x/2 <1/2
x < 1/2
Answer:
Equation of line in slope-intercept form that passes through (4, -8) and is perpendicular to the graph 
is below
Step-by-step explanation:
Slope of the equation 
is 
Since slopes of perpendicular lines are negative reciprocal of each other, therefore slope of other line is given as
Equation of line in point slope form is given as
Here (x1, y1) = (4, -8)
Simplifying it further
Answer:7
Step-by-step explanation:
all you have to do is subtract 20-13
