A. The figure is a triangular pyramid. You can findits surface area by adding up the area of the three faces of the triangle and the area of the base. A derived formula also is used where the SA is equal to 12 times the perimeter of base times the slant height, added to that is the area of the base. The area of the square base is s^2. Its perimeter is 4s.
SA of Pyramid = 12*P*l + s^2
SA of Pyramid = 12*4s*l + 16^2
SA of Pyramid = 12*4(16)*(17) + (16)^2
SA of Pyramid = 11,008 square inches
b.) The formula for the SA of a cone is:
SA of cone = πr[r+√(h^2+r^2)]
SA of cone = π(3)[(3+√(8^2+3^2)]
SA of cone = 108.8 square inches
Answer:
46.03 = 46.030
Step-by-step explanation:
they are the same nub,er except they put another zero at the end of the one on the right
don't be alarmed the two lines just mean absolute value, the problem is asking what is m. the problem is asking what number multipyed by 2, subtracted by 1 will give you 3?
2x2=4 right?
so 4-1=3 there!
m=4
so the problem is 2(4)-1=3
i hope i explained well enough!
To find 5 and 1/2 of 60 you would simply use the equation:
5.5*60=330
5 and 1/2 of 60 is 330.
Answer: h = 137.4 metres
Step-by-step explanation:
Given that the length of the shadow of a pole on level ground increase 90m, that is, (x + 90)m will be the total length of the shadow. Also we are given that the angle of elevation of the sum changes from 58-38.
To calculate the height, we will employ trigonometry ratio. SohCahToa which are: tan 58 and tan 38.
Please find the attached files for the solution
