Answer:
lattice parameter = 5.3355x10^-8 cm
atomic radius = 2.3103x10^-8 cm
Explanation:
known data:
p=0.855 g/cm^3
atomic mass = 39.09 g/mol
atoms/cell = 2 atoms
Avogadro number = 6.02x10^23 atom/mol
a) the lattice parameter:
Since potassium has a cubic structure, its volume is equal to:
v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]
substituting values:
v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3
but as the cell volume is
a^3 =v
![a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7Bv%7D%3D%5Csqrt%5B3%5D%7B1.5189x10%5E%7B-22%7D%20%7D%20%3D%205.3355x10%5E-8)
cm
for a BCC structure, the atomic radius is equal to
The moles of NaCl would be 0.2669277996234607 cause one gram of NaCl is equal to 0.017110756386119273 moles
Here first we will identify the number of significant figures in the given two dimensions
2.3mm : there are two significant numbers
8.00mm: there are three significant numbers
so we will report the answer to minimum number of significant number , which is two
the answer is 18.4
We will report it to be 18 mm^2
Tumor cells differ from normal cells in that A) Mitosis is not regulated in tumor cells.
This is seen when tumors grow to large amounts rather quickly. Mitosis is not regulated, and therefore the cells continue to multiply and that is when we are able to see and feel a palpable cancer mass - their growth is uncontrolled.
