<u>Answer:</u> The molarity of solution will be 0.049 M
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
We are given:
Given mass of sodium chloride = 10 g
Molar mass of sodium chloride = 58.44 g/mol
Volume of solution = 3.50 L
Putting values in above equation:
Hence, the molarity of solution will be 0.049 M
Explanation:
For the given reaction
Now, expression for half-life of a second order reaction is as follows.
....... (1)
Second half life of this reaction will be . So, expression for this will be as follows.
=
...(2)
where is the final concentration that is,
here and
is the initial concentration.
Hence, putting these values into equation (2) formula as follows.
=
= ...... (3)
Now, dividing equation (3) by equation (1) as follows.
=
= 3
or, = 3
Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.
Answer:
8.822 × 10¹³ g Co
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
Explanation:
<u>Step 1: Define</u>
9.015 × 10³⁵ atoms Co
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Co - 58.93 g/mol
<u>Step 3: Convert</u>
<u /> = 8.82189 × 10¹³ g Co
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
8.82189 × 10¹³ g Co ≈ 8.822 × 10¹³ g Co