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mylen [45]
3 years ago
5

How many atoms are in 2.5 moles of manganese?

Chemistry
1 answer:
yan [13]3 years ago
7 0

Answer:

You use the fact that 1 mole of any substance contains exactly 6.022⋅1023 atoms or molecules of that substance - this is known as Avogadro's number. In your case, 1 mole of gold will have exactly 6.022⋅1023 atoms of gold.

Explanation:

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Rewrite this measurement with a simpler unit, if possible. <br> 8.3 kg•m^2/ s^2
Feliz [49]

Answer: 8.3 J

Explanation:

We have the following measurement:

8.3 \frac{kg m^{2}}{s^{2}}

Rearranging the units:

8.3 \frac{kg m}{s^{2}}m

Since 1 Newton is 1 N=1 \frac{kg m}{s^{2}}:

8.3 Nm

Since 1 Joule is 1 J=1 Nm:

8.3 J This is the simplest form possible

7 0
3 years ago
The _______ are found on the right side of the arrow in a chemical reaction. A. reactants B. products C. subscripts D. coefficie
julia-pushkina [17]

Answer:

B. products are found on the write side of the arrow in a chemical reaction.

8 0
3 years ago
Read 2 more answers
Air, Sea water, alloy afe the examples of
ratelena [41]

Answer:

B. Mixture

because air,sea water and alloy are example of Mixture

8 0
3 years ago
Question 10
olga2289 [7]

Answer:

Here it would be A,B and C because all the examples are violating safety precautions. They are all examples of un safe signs.

Hope this helps

Explanation:

6 0
2 years ago
(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW
Aleonysh [2.5K]

Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = <em>2.3x10⁻³M  InF₃. </em>Thus:

[In⁺³] = 2.3x10⁻³M  InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M  In⁺³

[F⁻] = 2.3x10⁻³M  InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M  In⁺³] × [7.0x10⁻³M F⁻]³ = <em>7.9x10⁻¹⁰</em>

<em></em>

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, <em>solubility is 6.31x10⁻⁶M</em>

3 0
3 years ago
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