What is the value of x

what is the probability of drawing two yellow marbles if the first on is NOT place back into the bag before the second draw?

Kruka [31]

Answer:

1/45

Step-by-step explanation:

I assume there are 10 marbles total, 2 of which are yellow.

The probability the first marble is yellow is 2/10.

There's now one less marble, so the probability that the second marble is yellow is 1/9.

The total probability is (2/10) (1/9) = 1/45.

6 0

3 years ago

Is the sum of an odd number and an even number, even?

adelina 88 [10]

Answer:

No.

Step-by-step explanation:

Any even number plus any odd number will always be odd.

Hope this helps Buddy!

Please mark me brainliest!

~Courtney

5 0

3 years ago

Read 2 more answers

The estimate obtained from a sample of which of the following sizes would most likely be closest to the actual parameter value o

SOVA2 [1]

To obtain an estimate of a parameter of a population, we use confidence intervals.

Confidence intervals:

The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.

Thus, you should select the highest sample size in the options.

For more on confidence interval/margin of error, you can check brainly.com/question/22718960

6 0

3 years ago

The scores of individual students on the american college testing (act) program composite college entrance examination have a no

ryzh [129]

The sampling distribution standard deviation is the population standard deviation divided by the root of the sample size.

sampling distribution standard deviation = 6.00/√36 = 1.00

8 0

3 years ago

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A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago