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nadezda [96]
3 years ago
14

Simultaneous Linear equation ​

Mathematics
1 answer:
const2013 [10]3 years ago
3 0

.........?............

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Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug
gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems  

In C(5,3)=10ways, this can be achieved  

In part a:

Space sample chooses 3 of a 5 systems  

(M_1, \ M_2,\ M_3),(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort  

Outcomes probable =

(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6

\to p(A)=\frac{6}{10}\\\\

            =0.6

In point c:

B = highest effort that is M_5

Potential result=

(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6  \\\\

\to B= \frac{6}{10} \\\\

        =0.6

\to P(B)=10

In point d:

\to \ A  \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)

\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \

                                      =0.3

In point e:

\to (A \cup B) =  (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9\to P(A \cap B)=\frac{9}{10}

                    = 0.9

In point f:

\to (A\cap B) = \frac{3}{10}

                 = 0.3

In point g:

\to (A \cup B) = \frac{7}{10}

                 =0.7

In point h:

\to p(A \cap B) = 0.3 \neq 0

8 0
3 years ago
Find the area of the figure. Round to the nearest tenth if necessary.
baherus [9]

Hello!


First of all, let's find the triangle. As we can see, it is eight units long and four units tall. We can use the triangle formula and half the product.


4(8)=32

32/2=16


Now we need to find the area of the semicircle. We can use circle formulas and half our final answer. We will find the area using A=\pir².


We know that the diameter of this circle is eight. Therefore our radius is 4.


A=4\pi²

A=16\pi


Now we multiply.


16\pi≈50.27


Now we add our triangle.


50.27+16=66.27


The nearest answer to this is B)66.2. It may have been a bit over as we used \pi, not 3.14.


I hope this helps!



3 0
3 years ago
What is the range of the function below in set builder notation? y=|x-3|
Kisachek [45]

Answer:  \{y | \ y \in \mathbb{R}, \ y \ge 0\}

This translates to "y is any real number such that it is 0 or larger".

The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.

So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.

4 0
3 years ago
What is the value of u ?
shtirl [24]

Answer:

53

Step-by-step explanation:

you just need to reflect your lines to find answer.

6 0
3 years ago
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Cantaloupes are four for $ 9, how many can you buy for $25? which proportion is properly set up?
Lemur [1.5K]

Answer:

you can buy 2 two cantaloupes.

you'll have $7.00

7 0
3 years ago
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