Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So,
is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So,
would be 25°.
Now we can find
. As the sum of the internal angle of a triangle is 180°.

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
Subtraction will happen in this case.
14ft-5ft= 9ft
10 inches-8 inches= 2 inches
So, it grew 9ft. and 2 inches.

The inequality above shows the relationship.
In this case, Kareem miles on the left have to be at least as much as Christine's on the right.
It would read: 5x is greater than or equal to 6y.
He would’ve sold 12 candy bars.
12x3=36
He only sold 20 items so that leaves 8 cookies
5x8=40
40+36=76$
Answer:
°
Step-by-step explanation:



subtract
form both sides

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