Answer:
Cost of the pen = Rs.100
Step-by-step explanation:
Let the marked price = x
When the shopkeeper is selling for x, his gain = Rs. 20
Cost price = Marked price - Gain = x - 20 --------(I)
After discount:
Discount = 10%
Marked price after discount = (100 - 10)% of x = 90% of x
= 0.9 * x = 0.9x
When the shopkeeper is selling for 0.9x, his gain = Rs.8
Cost price = Marked price - gain = 0.9x - 8 -------(II)
From (I) and (II)
x - 20 = 0.9x - 8
x = 0.9x - 8 + 20
x = 0.9x + 12
x - 0.9x = 12
0.1x = 12
x = 12/0.1
x = 120
Marked price of pen = Rs.120
Cost price = 120 - 20
Cost price = Rs. 100
Answer:
1/5 is the answer
Step-by-step explanation:
its the greatest fractions, out of the options you picked
Answer:
He has 11 quarters
Step-by-step explanation:
* Lets study the information in the problem to solve it
- The value of dimes and quarters is $6.35
- There are dimes and quarters
- The dime = 10 cents
- The quarter = 25 cents
* We must change the money from dollars to cents
∵ $1 = 100 cents
∴ $6.35 = 6.35 × 100 = 635 cents
- The number of dimes = 3 + 3 × number of quarters
* Let number of dimes is D and number of quarter is Q
∴ D = 3 + 3Q
∴ 10D + 25Q = 635
* Substitute the value of D from first equation in the second equation
∴ 10(3 + 3Q) + 25Q = 635 ⇒ open the bracket
∴ 10(3) + 10(3Q) + 25Q = 635
∴ 30 + 30Q + 25Q = 635 ⇒ collect like terms
∴ 30 + 55Q = 635 ⇒ subtract 30 from both sides
∴ 55Q = 605 ⇒ divide both sides by 55
∴ Q = 11
* He has 11 quarters
x + 2