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xxTIMURxx [149]
4 years ago
9

Using the following set of data, calculate the lower quartile, the upper quartile, and the interquartile range. 20, 22, 25, 28,

29, 30, 32, 33, 34
Plz show the lower quartile,the upper quartile and the interguartile range vest answer will be marked as brainliest
Mathematics
1 answer:
Rufina [12.5K]4 years ago
3 0
  lower quartile          upper quartile
{20, 22, 25, 28, }29,{ 30, 32, 33, 34}
           |              |              |
   Q1-(23.5) Q2(29)     Q3(32.5)

Interquartile range= Q3-Q1=32.5-23.5=9
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Salsk061 [2.6K]

Answer:

Here is the process I did:

2(6x+4)-6+2x=3(4x+3)+1

Step 1: Distribute the 2 to the numbers in the parentheses (6x +4) on the left side of the equation

6x(2)+4(2)-6+2x=3(4x+3)+1

12x+8-6+2x=3(4x+3)+1

Step 2: On the left side of the equation combine like terms

x's go with x's (12x and 2x):

(12x + 2x)+8-6=3(4x+3)+1

14x+8-6=3(4x+3)+1

normal numbers go with normal numbers ( 8 and -6):

14x+(8+(-6))=3(4x+3)+1

14x+2=3(4x+3)+1

Step 3: Distribute the 3 to the numbers in the parentheses (4x+3) on the right side of the equation

14x+2=4x(3) +3(3) + 1

14x+2=12x + 9 + 1

Step 4: On the right side of the equation combine like terms

normal numbers go with normal numbers ( 9 and 1):

14x+2=12x + (9 + 1)

14x+2=12x + 10

Step 5: Bring 2 from the left side to the right by subtracting it to both sides

14x+(2-2)=12x + (10-2)

14x = 12x + 8

Step 6: Bring 12x from the right side to the left by subtracting it to both sides

(14x - 12x) = (12x - 12x) + 8

2x = 8

Step 7: Isolate x by dividing 2 to both sides

x = 4

Hope this helped!

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Answer:

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Step-by-step explanation:

We are given the following in the question:

The mean score of 8 players is 14.5.

Let x denote the highest score.

If x is removed, the mean of the score of the remaining 7 players is 12.

Formula for mean:

\bar{x} = \dfrac{\displaystyle\sum x_i}{n}

Putting values, we get:

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Thus, the highest score is 32.

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Step-by-step explanation:

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