Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
80 would be your answer for this question
Answer:
the base length is 8 units
Step-by-step explanation:
You can use pythagorean theorem to solve this
8 x 6 = 48
52 - 48 = 4
so
<span>52÷8 = 6 4/8
answer
</span><span>quotient = 6
</span><span>remainder = 4</span>
Answer:
Option 2.
Step-by-step explanation:
f(x) = - x^2 + 3
The parent function is x^2
- the '-' before the x^2 reflects it in the x-axis, and the + 3 shifts it up 3 units.
