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Lelechka [254]
3 years ago
15

(6 pt) Match each word from Column A with the correct definition from Column B. Column A Column B 1. element 2. compound 3. reac

tion 4. catalyst 5. neutralize 6. conservation A. to make an acid or base chemically neutral B. the keeping of animals, people, or places safe C. a substance made up of two or more elements D. a substance that is made of only one kind of atom E. a substance that increases the rate of a reaction but is not used up F. a process by which certain chemicals interact to form new products
Chemistry
1 answer:
Marat540 [252]3 years ago
3 0
1. D
2. C
3. F
4. E
5. A
6. B
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is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that carbonic acid can undergo when it's d
Burka [1]

Answer:

H₂CO₃   H₂O  ⇄  HCO₃⁻  +  H₃O⁺          Ka1

HCO₃⁻  +  H₂O  ⇄  CO₃⁻²  +  H₃O⁺        Ka2

CO₃⁻²  +  H₂O  ⇄  HCO₃⁻   +  OH⁻       Kb1

HCO₃⁻  +  H₂O  ⇄   H₂CO₃  +  OH⁻     Kb2

Explanation:

Formula for carbonic acid is: H₂CO₃

It is a dyprotic acid, because it can release two protons. We can also mention that is a weak one. The equilibrums are:

H₂CO₃   H₂O  ⇄  HCO₃⁻  +  H₃O⁺          Ka1

HCO₃⁻  +  H₂O  ⇄  CO₃⁻²  +  H₃O⁺        Ka2

When the conjugate strong bases, carbonate and bicarbonate take a proton from water, the reactions are:

CO₃⁻²  +  H₂O  ⇄  HCO₃⁻   +  OH⁻       Kb1

HCO₃⁻  +  H₂O  ⇄   H₂CO₃  +  OH⁻     Kb2

Notice, that bicarbonate anion can release or take a proton to/from water. This is called amphoteric,

6 0
3 years ago
_____ Ni(OH)2 + _____ H2(SO4) → _____ Ni(SO4) + _____ H2O this is balancing chemical equations I need help fast
weqwewe [10]
Ni(OH)2+H2SO4=NiSO4+2H2O
Double Replacement Reaction
5 0
3 years ago
A chemist dissolves 697. mg of pure potassium hydroxide in enough water to make up 160. mL of solution. Calculate the pH of the
umka21 [38]

<u>Answer:</u> The pH of the solution is 12.9

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of KOH = 697 mg = 0.697 g    (Conversion factor:  1 g = 1000 mg)

Molar mass of KOH = 56 g/mol

Volume of solution = 160 mL

Putting values in above equation, we get:

\text{Molarity of KOH solution}=\frac{0.697\times 1000}{56\times 160}\\\\\text{Molarity of KOH solution}=0.0778M

1 mole of KOH produces 1 mole of K^+ ions and 1 mole of OH^- ions

To calculate the pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=0.0778M

Putting values in above equation, we get:

pOH=-\log (0.0778)=1.11

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH=14-1.11=12.89

Hence, the pH of the solution is 12.9

5 0
3 years ago
Which of the following chemical equations is correctly balanced?
olga55 [171]
The correct answer is B.
3 0
3 years ago
Read 2 more answers
The Environmental Protection Agency has determined that safe drinking
dmitriy555 [2]

Answer:

b) \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}

The confidence interval for this case is given (6.21, 6.59)

So we can conclude at 95% of confidence that the true mean for the PH concentration is between 6.21 and 6.59 moles per liter

c) Since the confidence interval not contains the value 7 we reject the hypothesis that the true mean is equal to 7. And the same result was obtained with the t test for the true mean.

Explanation:

We assume that part a is test the claim. And we can conduct the following hypothesis test:

Null hypothesis: \mu =7

Alternative hypothesis \mu \neq 7

The statistic is to check this hypothesi is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

We know the following info from the problem:

\bar X = 6.4 , s=0.5, n =30

Replacing we got:

t = \frac{6.4-7}{\frac{0.5}{\sqrt{30}}}= -6.573

And the p value would be:

p_v= 2*P(Z

Since the p value is very low compared to the significance assumed of 0.05 we have enough evidence to reject the null hypothesis that the true mean is equal to 7 moles/liter

Part b

The confidence interval is given by:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}

The confidence interval for this case is given (6.21, 6.59)

So we can conclude at 95% of confidence that the true mean for the PH concentration is between 6.21 and 6.59 moles per liter

Part c

Since the confidence interval not contains the value 7 we reject the hypothesis that the true mean is equal to 7. And the same result was obtained with the t test for the true mean.

6 0
3 years ago
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