Answer:
The class of this compound is <u>aldehyde or ketone (i).</u>
Explanation:
Absorption peak at 1720 cm-1 shows the presence of a carbonyl group, possibly an aldehyde or ketone with C=O bond.
Further information on molecular formula would be required for structural elucidation.
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Answer:
The specific gravity of the rock with respect to water is equal to 3
Explanation:
To solve the question, we list out the variables as follows
Mass of rock = 6 grams
Mass of equal volume of water = 2 grams
Specific gravity or relative density is the mass of a unit volume of a substance divided by the mass of an equal volume of a reference material.
Specific gravity = (mass of substance)/(mass of equal volume of water)
Therefore the specific of the rock sample is = (mass of cube of rock sample)/(mass of same-sized cube of water)
= (6 grams)/(2 grams) = 3
The specific gravity of the rock = 3
It is True. Hope this helped.