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Naya [18.7K]
3 years ago
8

How do you solve 3×(9+2-8÷16)

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0
Remember order of operations (PEMDAS):

3•(11-1/2)
3•10.5
31.5
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Write 3.79 as a mixed number.
snow_lady [41]

Answer:

379/100

Step-by-step explanation:

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5 0
4 years ago
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A piece of paper has a length of 12cm and a width of 8cm. What is it's perimeter
Nata [24]
P = 2(12+8)
P = 2(20)
P = 40

answer: <span>perimeter = 40 cm</span>
4 0
3 years ago
Find the rectangular coordinates of (7, 150°)
Y_Kistochka [10]

Answer:

The coordinates are (-7sqrt(3)/2, 7/2).

Step-by-step explanation:

The rectangular coordinates from polar coordinates is found by:

x = r*cos(theta)

y = r*sin(theta)

Substituting the given values, we get:

x = 7*cos(150 deg) = 7*(-sqrt(3)/2) = -7sqrt(3)/2

y = 7*sin(150 deg) = 7*(1/2) = 7/2

The coordinates are (-7sqrt(3)/2, 7/2).

I hope this helps! :)

4 0
3 years ago
How do we figure this out
lisov135 [29]

Answer:

Pair 1: 10 cm and 2 cm. and the sum is 12 cm.

Pair 2: 20 cm and 4 cm. and the sum is 24 cm.

Step-by-step explanation:

Area of a rectangle is given by A = LW, where L is the length and W is the width of the rectangle.

Pair 1:

For the first rectangle W = 4 cm and A = 40 sq, cm

Then L = \frac{A}{W} = \frac{40}{4} = 10 cm.

For the second rectangle W = 4 cm and A = 8 sq, cm

Then L = \frac{A}{W} = \frac{8}{4} = 2 cm.

Therefore, the sum of two unknown lengths = 10 + 2 = 12 cm. (Answer)

Pair 2:

For the first rectangle W = 4 cm and A = 80 sq, cm

Then L = \frac{A}{W} = \frac{80}{4} = 20 cm.

For the second rectangle W = 4 cm and A = 16 sq, cm

Then L = \frac{A}{W} = \frac{16}{4} = 4 cm.

Therefore, the sum of two unknown lengths = 20 + 4 = 24 cm. (Answer)

8 0
3 years ago
If the foreign exchange rate between the U.S. dollar and the Japanese yen is 1:90, how many yen will you get for $15?
Ipatiy [6.2K]

Answer:

1350 yen

Step-by-step explanation:

90x15=1350

5 0
3 years ago
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