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Fynjy0 [20]
3 years ago
11

Light and sound waves both share what characteristic? (2 points)

Physics
2 answers:
KonstantinChe [14]3 years ago
7 0

Answer:

a They both exhibit the Doppler effect.

Explanation:

When source of light or sound and the observer will move relative to each other then due to relative motion of them the frequency of light or sound that is observed by the observer is different from its actual frequency. This phenomenon is known as Doppler's effect.

So here the same characteristic that is exhibit by both is Doppler effect

apart from this

Light is transverse in nature while sound wave is longitudinal

Sound moves faster in water while light moves fastest in air

light do not requires any medium while sound requires medium to travel

so correct answer will be

a They both exhibit the Doppler effect.

beks73 [17]3 years ago
6 0

Answer:

Answer (A) They both exhibit the Doppler effect.

Explanation:

The Doppler effect, or Doppler shift, describes the changes in frequency of any kind of sound or light wave produced by a moving source with respect to an observer. Waves emitted by an object traveling toward an observer get compressed — prompting a higher frequency — as the source approaches the observer.

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Sergeu [11.5K]

Answer:CCCCCCCCCCCCCCCCC

Explanation:CCCCCCCCCCCCC

4 0
3 years ago
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The total amount of electrical energy used by a
tia_tia [17]

The amount of electrical energy used by the television is given by:

E=Pt

where P is the power of the device and t is the time.


The power of the television is P=315 W, while the total time is

t=30.0 min \cdot 60 =1800 s

If we substitute these numbers into the formula, we find the energy:

E=Pt=(315 W)(1800 s)=5.67 \cdot 10^5 J


so, the correct answer is

(1) 5.67 × 10^5 J

7 0
3 years ago
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A 13.5 μF capacitor is connected to a power supply that keeps a constant potential difference of 22.0 V across the plates. A pie
-BARSIC- [3]

a) 3.27\cdot 10^{-3} J

b) 11.60\cdot 10^{-3} J

c) 8.33\cdot 10^{-3} J

Explanation:

a)

The energy stored in a capacitor is given by

U=\frac{1}{2}CV^2

where

C is the capacitance of the capacitor

V is the potential difference across the plates of the capacitor

For the capacitor in this problem, before insering the dielectric, we have:

C=13.5 \mu F = 13.5\cdot 10^{-6}F is its capacitance

V = 22.0 V is the potential difference across it

Therefore, the initial energy stored in the capacitor is:

U=\frac{1}{2}(13.5\cdot 10^{-6})(22.0)^2=3.27\cdot 10^{-3} J

b)

After the dielectric is inserted into the plates, the capacitance of the capacitor changes according to:

C'=kC

where

k = 3.55 is the dielectric constant of the material

C is the initial capacitance of the capacitor

Therefore, the energy stored now in the capacitor is:

U'=\frac{1}{2}C'V^2=\frac{1}{2}kCV^2

where:

C=13.5\cdot 10^{-6}F is the initial capacitance

V = 22.0 V is the potential difference across the plate

Substituting, we find:

U'=\frac{1}{2}(3.55)(13.5\cdot 10^{-6})(22.0)^2=11.60\cdot 10^{-3} J

C)

The initial energy stored in the capacitor, before the dielectric is inserted, is

U=3.27\cdot 10^{-3} J

The final energy stored in the capacitor, after the dielectric is inserted, is

U'=11.60\cdot 10^{-3} J

Therefore, the change in energy of the capacitor during the insertion is:

\Delta U=11.60\cdot 10^{-3}-3.27\cdot 10^{-3}=8.33\cdot 10^{-3} J

So, the energy of the capacitor has increased by 8.33\cdot 10^{-3} J

8 0
3 years ago
Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha
GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

So,

Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

4 0
3 years ago
What must you know in order to determine the gravitational force between two objects?
Ganezh [65]
You must know the masses of both objects and the gravitational constant used to calculate the gravitational force between the 2 objects.
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