1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iragen [17]
3 years ago
7

You used three methods of analysis to find the acceleration of the cart on the track: a two-point difference from v(t), an avera

ge of a(t) that was itself calculated by a succession of first differences of the v(t) data, and a line fit to v(t). some criteria to help you consider which method is best are part a in which type of graph(s) is it easiest to see whether the acceleration was constant?
Physics
2 answers:
Oxana [17]3 years ago
6 0

<u><em>The correct method to obtain the constant acceleration of the cart is to obtain a straight line of the velocity-time data on the graph.</em></u>

Explanation:

The acceleration of an object is explained as change in velocity of the body every second while it is in motion. If the rate at which the velocity of object changes remains constant, acceleration of object remains constant.

The acceleration is basically the magnitude of increment in velocity of the body after every second. The graph between the velocity and time is the plot of the velocity of body at different instants.

The slope of the velocity time graph of the body is the rate of change of velocity of the body. The slope of the v-t graph keeps changing, then the velocity of the body changes with a non-constant acceleration.

Whereas if the slope of a body is a straight line, then the acceleration of the body is constant and its velocity also changes at a constant rate.

Thus, <u><em>the correct method to obtain the constant acceleration of the cart is to obtain a straight line of the velocity-time data on the graph.</em></u>

Learn More:

1. Change in momentum of the car due to collision brainly.com/question/9484203

2. The acceleration of the book kept on the table brainly.com/question/9719731

3. Magnitude of acceleration of the car brainly.com/question/6423792

Answer Details:

Grade: High School

Subject: Physics

Chapter: Acceleration

Keywords:

acceleration, rate of change, velocity, velocity-time graph, constant, non-constant, slope, straight line, cart, three methods.

Burka [1]3 years ago
4 0
The best way to find that you want is the line fit. When acceleration is constant the speed(v) changes smoothly every moment, so the v line must be straight. Differently, the accelaration changes.
You might be interested in
We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one
Len [333]

Answer:

A=1

B=-2

Explanation:

Part A and B of the question wasn't given, however, I attached the relevant parts to solve this question as follows.

From part B as attached, it shows that the right option is C which is

2A+3B=-4

Substituting B with 3A-5 then we form the second equation as shown

2A+3(3A-5)=-4

By simplifying the above equation, we obtain

2A+9A-15=-4

Re-arranging, then

11A=-4+15

Finally

11A=11

A=1

To obtain B, we already know that 3A-5 so substituting the value of A into the above then we obtain

B=3(1)-5=-2

Therefore, required values are 1 and -2

3 0
3 years ago
A convection cell is BEST described as ___.
Helga [31]
D, a loop of moving air
6 0
3 years ago
A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can
Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

\mu is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

v=85 mph \cdot \frac{1609}{3600}=38.0 m/s is the speed

And solving for \mu, we find the coefficient of friction required to keep the car in circular motion:

\mu = \frac{v^2}{rg}=\frac{38.0^2}{(750)(9.8)}=0.196

Learn more about circular motion:

brainly.com/question/2562955  

brainly.com/question/6372960  

#LearnwithBrainly

8 0
3 years ago
A meter stick is balanced at the 50 cm mark. You tie a 20 N weight at the 20 cm mark. Where should a 30 N weight be placed so th
vivado [14]

Answer:

20 cm to the right of the center or 20+50 = 70 cm from the left side.

Explanation:

The length of meter stick is 1 m = 100 cm

Balance point on 50 cm

From the center the 20 N weight is 50-20 = 30 cm

Torque is obtained when force is multiplied with the distance

As the force is conserved we have

\dfrac{20}{30}\times 30=20\ cm

The distance will be 20 cm to the right of the center or 20+50 = 70 cm from the left side.

7 0
2 years ago
You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 286.0 kPa when the ther
diamong [38]

Answer:

T_{2} = 606.69 K

Explanation:

In that the gas thermometer is a constant volume, it is satisfied that:

\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }  

How the boiling water is under regular atmospheric pressure, then

T_{1} = 373 .15 K

Thus

\frac{286000}{373.15} = \frac{465000}{T_{2} }

T_{2} = 606.69 K

5 0
2 years ago
Other questions:
  • 1. A container has a mass of 36 kg. How much does the container weigh?
    11·2 answers
  • Vector a s is 2.80 cm long and is 60.0° above the x-axis in the first quadrant. vector b s is 1.90 cm long and is 60.0° below th
    12·1 answer
  • Both physical feature and behaviors can be inherited<br><br> True<br> False
    9·1 answer
  • What do nebulae have the most in common with?
    12·1 answer
  • A helicopter lifts a 66 kg astronaut 15 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/
    7·1 answer
  • A car is travelling at a constant speed on a flat road
    9·1 answer
  • The potential energy of an object is equal to the work required to lift it into position. True or False?
    10·2 answers
  • A car travels in a straight line for 4.4 h at a constant speed of 81 km/h. What is its acceleration?
    14·2 answers
  • Help please ! Ill give brainliest !! ☁️✨
    7·1 answer
  • Why is it advised to tie any luggage kept on the roof of a bus with a rope?​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!