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iragen [17]
4 years ago
7

You used three methods of analysis to find the acceleration of the cart on the track: a two-point difference from v(t), an avera

ge of a(t) that was itself calculated by a succession of first differences of the v(t) data, and a line fit to v(t). some criteria to help you consider which method is best are part a in which type of graph(s) is it easiest to see whether the acceleration was constant?
Physics
2 answers:
Oxana [17]4 years ago
6 0

<u><em>The correct method to obtain the constant acceleration of the cart is to obtain a straight line of the velocity-time data on the graph.</em></u>

Explanation:

The acceleration of an object is explained as change in velocity of the body every second while it is in motion. If the rate at which the velocity of object changes remains constant, acceleration of object remains constant.

The acceleration is basically the magnitude of increment in velocity of the body after every second. The graph between the velocity and time is the plot of the velocity of body at different instants.

The slope of the velocity time graph of the body is the rate of change of velocity of the body. The slope of the v-t graph keeps changing, then the velocity of the body changes with a non-constant acceleration.

Whereas if the slope of a body is a straight line, then the acceleration of the body is constant and its velocity also changes at a constant rate.

Thus, <u><em>the correct method to obtain the constant acceleration of the cart is to obtain a straight line of the velocity-time data on the graph.</em></u>

Learn More:

1. Change in momentum of the car due to collision brainly.com/question/9484203

2. The acceleration of the book kept on the table brainly.com/question/9719731

3. Magnitude of acceleration of the car brainly.com/question/6423792

Answer Details:

Grade: High School

Subject: Physics

Chapter: Acceleration

Keywords:

acceleration, rate of change, velocity, velocity-time graph, constant, non-constant, slope, straight line, cart, three methods.

Burka [1]4 years ago
4 0
The best way to find that you want is the line fit. When acceleration is constant the speed(v) changes smoothly every moment, so the v line must be straight. Differently, the accelaration changes.
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Explain two ways in which humans are related<br>to whales.​
Maksim231197 [3]

Answer:

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3 years ago
A cue ball, moving with 9.0 N·s of momentum strikes the nine-ball at rest. The nine-ball moves off with 2.0 N·s in the original
lisov135 [29]

Answer:

P = 7.28 N.s

Explanation:

given,

initial momentum of cue ball in x- direction,P₁ = 9 N.s

momentum of nine ball in  x-  direction, P₂ = 2 N.s

momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s

momentum of the cue after collision = ?

using conservation of momentum

in x- direction

P₁ + p = x  + P₂

p is the initial momentum of the nine balls which is equal to zero.

9 + 0  = x  + 2

x = 7 N.s

momentum in x-direction.

equating along y-direction

P'₁ + p = y + P'₂

0 + 0 = y + 2

y = -2 N.s

the momentum of the cue ball after collision is equal to resultant of the momentum .

P = \sqrt{x^2+y^2}

P = \sqrt{7^2+(-2)^2}

      P = 7.28 N.s

the momentum of the cue ball after collision is equal to P = 7.28 N.s

7 0
3 years ago
Which scientific method could I use to test this hypothesis? "If the mass and the volume of an object are known, then its densit
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Answer:

Multiple so you can test multiple hypothesis at once

Explanation:

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3 0
2 years ago
Read 2 more answers
A bullet is shot from a rifle with a velocity of 720.0 m/s what time is required for the bullet to strike a target 324.0m to the
Basile [38]

The bullet will strike the target placed in 324.0 m in the East in 0.45 seconds.

<u>Explanation:</u>

As we all know the epic relation between distance, speed and time; we cam easily estimate the time in which an object can reach to the destination or target.

As here in this case, we know the distance of the target and the velocity of a bullet exerted from a rifle given as follows,

Distance of the Target from the rifle edge = 324.0 m

Velocity of bullet exerted from the rifle = 720 m/s

Since we know that,

      \text {velocity}=\frac{\text {distance}}{\text {time}}

or

       \text {Time}=\frac{\text {distance}}{\text {velocity}}

We can simply implement all the values in the formula and get the results i.e the time required by the bullet to hit the target. Since both the values are in S.I units measures, we don't need to change or convert any of them. Hence,

       \text { Time }=\frac{324}{75}=0.45 \text { seconds }

Therefore, the bullet will hit the target in 0.45 seconds.

4 0
3 years ago
A pitcher can throw a baseball at about 90 miles/hour (about 39.6 m/s). What is the ratio of the kinetic energy to the rest ener
tester [92]

Answer:

8.71*10^{-15}

Explanation:

The rest energy is the energy associated with the base ball at zero velocity which is expressed as

Rest energy=mc^{2}\\

Note: the speed C is the speed of light which is expressed as 3*10^8

while the kinetic energy is the energy associated with the ball during its motion and is expressed as

Kinetic energy=1/2mv^{2}

the ratio can be expressed as

\frac{Kinetic Energy}{Rest Energy}=\frac{\frac{1}{2}mv^{2} }{mc^{2}}\\since V=39.6m/s\\C=3*10^{8}m/s\\\frac{Kinetic Energy}{Rest Energy}=\frac{\frac{1}{2}39.6^{2} }{(3*10^8)^{2}} \\\frac{Kinetic Energy}{Rest Energy}=\frac{784.08}{9*10^{16}} \\\frac{Kinetic Energy}{Rest Energy}=8.71*10^{-15}

5 0
4 years ago
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