1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iragen [17]
4 years ago
7

You used three methods of analysis to find the acceleration of the cart on the track: a two-point difference from v(t), an avera

ge of a(t) that was itself calculated by a succession of first differences of the v(t) data, and a line fit to v(t). some criteria to help you consider which method is best are part a in which type of graph(s) is it easiest to see whether the acceleration was constant?
Physics
2 answers:
Oxana [17]4 years ago
6 0

<u><em>The correct method to obtain the constant acceleration of the cart is to obtain a straight line of the velocity-time data on the graph.</em></u>

Explanation:

The acceleration of an object is explained as change in velocity of the body every second while it is in motion. If the rate at which the velocity of object changes remains constant, acceleration of object remains constant.

The acceleration is basically the magnitude of increment in velocity of the body after every second. The graph between the velocity and time is the plot of the velocity of body at different instants.

The slope of the velocity time graph of the body is the rate of change of velocity of the body. The slope of the v-t graph keeps changing, then the velocity of the body changes with a non-constant acceleration.

Whereas if the slope of a body is a straight line, then the acceleration of the body is constant and its velocity also changes at a constant rate.

Thus, <u><em>the correct method to obtain the constant acceleration of the cart is to obtain a straight line of the velocity-time data on the graph.</em></u>

Learn More:

1. Change in momentum of the car due to collision brainly.com/question/9484203

2. The acceleration of the book kept on the table brainly.com/question/9719731

3. Magnitude of acceleration of the car brainly.com/question/6423792

Answer Details:

Grade: High School

Subject: Physics

Chapter: Acceleration

Keywords:

acceleration, rate of change, velocity, velocity-time graph, constant, non-constant, slope, straight line, cart, three methods.

Burka [1]4 years ago
4 0
The best way to find that you want is the line fit. When acceleration is constant the speed(v) changes smoothly every moment, so the v line must be straight. Differently, the accelaration changes.
You might be interested in
I'm confusion, can I please get help???
kotykmax [81]

Answer:

Anything below 7.0 is acidic, so the range would be 0 to 7.

Neutral is simply 7, in the middle of the scale.

Lastly, anything above 7.0 is basic or alkaline, so that would be 7 to 14.

Good luck, I hope this helps

7 0
3 years ago
A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
vivado [14]

Their velocity afterwards is 2.88 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, for an isolated system (= no external force), the total momentum must be conserved before and after the collision. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1 + m_2)v

where: in this case:

m_1 = 91.5 kg is the mass of the first player

u_1 = 2.73 m/s is the initial velocity of the first player (choosing east as positive direction)

m_2 = 63.5 kg is the mass of the second player

u_2 = 3.09 m/s is the initial velocity of the second player

v is their combined velocity afterwards

Solving for v, we find:

v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(2.73)+(63.5)(3.09)}{91.5+63.5}=2.88 m/s

And the sign is positive, so the direction is east.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

7 0
3 years ago
If a wave has amplitude of 2 meters, a wavelength of 2 meters, and a frequency of 10 Hz, and a period of 1 second, then at what
Serhud [2]

Answer:

20 m/s

Explanation:

The speed of a wave is given by:

v=\lambda f

where

\lambda is the wavelength

f is the frequency

v is the speed

For the wave in this problem,

f = 10 Hz is the frequency

\lambda=2 m is the wavelength

So the speed is

v=(10 Hz)(2 m)=20 m/s

6 0
3 years ago
During the first 50 s a truck traveled at constant speed of 25 m/s. Find the distance that it is traveled.
Allushta [10]
Time=50s
speed=25m/s

Distance = speed×time
=25×50
=1250m

DISTANCE TRAVELLED IS =1250m

6 0
3 years ago
A geothermal plant has been built in a location. Which of these is the most likely benefit of the geothermal plant in this locat
kramer

Answer:

C

Explanation:

A and B are not true and D is a disadvantage

4 0
3 years ago
Other questions:
  • Which characteristics do all terrestrial planets have?
    13·2 answers
  • Can anyone explain the seasons of the earth?
    7·1 answer
  • Sick person develops a fever physical or chemical
    12·1 answer
  • As air temperature approaches the dew point, what happens to the relative humidity?
    15·2 answers
  • On a foggy day, you are driving at 70 mph and Granny is driving at 50 mph. As you try to pass her, you both see an overturned tr
    14·1 answer
  • A 110-pound person pulls herself up 4.0 feet. This took her 2.5 seconds. How much power was developed?
    11·2 answers
  • Drag each tile to the correct box a chemical reaction takes place in which energy is released arrange the reactions characterist
    8·1 answer
  • A car of mass M traveling with velocity v strikes a car of mass M that is at rest. The two cars’ bodies mesh in the collision. T
    12·1 answer
  • Defects of vision and their correction drawing ​<br><br>No Spams ❌❌
    11·2 answers
  • Which option is an example of an object that has potential energy followed by an object that has kinetic energy?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!