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2 years ago

My son and I are stuck on this one. Can anyone give some insight to this problem? Thank you.

Mathematics

1 answer:

omeli [17]2 years ago

3 0

Answer:

I made is clear for you, now you may match each one

Step-by-step explanation:

f(1)= 11, f(n)= 3*f(n-1)

11*3= 33, 33*3= 99, 99*3= 297, ...

11, 33, 99, 297...

⊕ middle

f(1)= -18, f(n)= f(n-1)+21

-18+21= 3, 3+21= 24, 24+21= 45, ...

-18, 3, 24, 45, ...

f(1)= -18, f(n)= f(n-1) + 22

-18+22= 4, 4+22= 26, 26+22= 48, ...

-18, 4, 26, 48, ...

f(1)= -18, f(n)= 2*f(n-1)

-18*2= -36, -36*2= -72, -72*2= -144, ...

- 18, -36, -72, -144...

⊕ bottom

f(1)= -18, f(n)= 6*f(n-1)

-18*6= -108, -108*6= -648, -648*6= -3888, ...

- 18, - 108, - 648, -3888, ...

⊕ top

f(1)= 11, f(n)= f(n-1) + 22

11+22= 33, 33+22= 55, 55+22= 77, ...

11, 33, 55, 77, ...

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Answer:

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Step-by-step explanation:

7$-2.50$=4.50$

4.50$ / .75$ = 6

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2 years ago

Look at the number line below. Tyhe number 2 is between 1 and 4 since 1 =1 and 4=2, that means that 2 must be between what two i

Vlada [557]

Answer: i dont know

Step-by-step explanation:

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2 years ago

HELP ME OUT PLEASE!!!

ANTONII [103]

Answer:

D) y= 4x - 1

Step-by-step explanation:

We are basically trying to see which of the equations provided are true on both sides of the equal sign when you plug in the x and y values.

Let's start!

Choice A:

plug in 0 for x and -1 for y

-1 = 4(0)

And you are left with...

-1 = 0

This equation is false! Therefore it does not match the function in the table

Choice B:

plug in the values again

-1 = 0 + 1

-1 = 1

False!

Choice C:

-1 = 0 + 5

-1 = 5

False!

Lastly...Choice D:

-1 = 4(0) -1

Multiply 4 and 0 which is 0, so you are left with...

-1 = -1

This equation is true!!

So your answer is D

Hope this helps :D

7 0

2 years ago

Whats the answer for number 11?

viva [34]

Answer:

Option 4

Step-by-step explanation:

y = -5x + 2

-8 = -5(2) + 2

-8 = -10 + 2

Correct! :)

4 0

2 years ago

out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i

Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that $P(A \cup B) = 0.95$

80% passed in mathematics 75% passed in english

This means that $P(A) = 0.8, P(B) = 0.75$

Proportion who passed in both:

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

Considering the values we have for this problem

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6$

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

$0.6t = 3000$

$t = \frac{3000}{0.6}$

$t = 5000$

5000 students appeared in the examination.

4 0

2 years ago