There are a lot of solutions to this problem, so I'm only going to list 10. The only requirement is that the quadrilateral must be a rectangle with a perimeter of 120 meters. 1) 30, 30, 30, 30. I know that this is a square, but it should still be a solution since all squares are rectangles. 2) 50, 50, 10, 10. 3) 55, 55, 5, 5. 4) 45, 45, 15, 15. 5) 40, 40, 20, 20. 6) 35, 35, 25, 25. 7) 36, 36, 24, 24. 8) 18, 18, 52, 52. 9) 14, 14, 48, 48 10) 6, 6, 54, 54.
We can list out each of the numbers' prime factors first before deciding their greatest common factor.
16: 2 × 2 × 2 × 2
48: 2 × 2 × 2 × 2 × 3
As you can see the bolded parts, these are the common factors of the two numbers. To find the greatest common factors, we just have to multiply all their common factors together.
Greatest common factor of 16 & 48: 2 × 2 × 2 × 2 = 16
