For any values less than -3, the answer is undefined, because then you have a negative value for √x+3
Answer:
250 mins
Step-by-step explanation:
since number of taps times time is constant
Answer:
When we have a number like:
1.0x10^n
To rewrite this in standard form, we need to:
if n is positive, we move the decimal point n times to the right, adding zeros when necessary.
1.0x10^3
n = 3. then we add 3 zeros between the one and the decimal point, this is:
1.0x10^3 = 1000
if n< 0, then we move the decimal point n times to the left.
If we had:
1.0x10^-3
We move the decimal point 3 times to the left, adding zeros as this is needed.
1.0x10^-3 = 0.001
if n = 0, we have:
1.0x10^0 = 1.0
Now let's rewrite all the given numbers:
A) 3.4x10^-1 = 0.34
B) 1.36x10^6 = 1360000
C) 7.9x10^0 = 7.9
D) 2.4x10^5 = 240000
E) 5.21x10^-3 = 0.00521
F) 4.3x10^-2 = 0.043
Answer:
The probability that the two rats are from the first litter is 14.28%, and the probability that the two rats are from the second litter is 34.28%.
Step-by-step explanation:
Since a cage holds two litter of rats, and one litter comprises one female and five males, while the other litter comprises seven females and two males, and a random selection of two rats is done, to find the probability that the two rats are from the same litter the following calculation must be performed:
6/15 x 5/14 = 0.1428
9/15 x 8/14 = 0.3428
Therefore, the probability that the two rats are from the first litter is 14.28%, and the probability that the two rats are from the second litter is 34.28%.
ANSWER
The height of the larger cone is 3cm
EXPLANATION
Since the two cones are similar we can use the scale factor to determine the height of the larger cone.
It was given that, the volume of the larger cone is 27 cm³ and the volume of the smaller cone is 8 cm³.
The scale factor for the volume is
The scale factor for the length is
![k = \sqrt[3]{ \frac{27}{8} }](https://tex.z-dn.net/?f=k%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B27%7D%7B8%7D%20%7D%20)
To find the height of the larger cone, we multiply by
