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ASHA 777 [7]
4 years ago
11

Name four angles between 0 and 360 degrees with a reference angle of 20 degrees Show work

Mathematics
2 answers:
nignag [31]4 years ago
8 0

Answer with explanation:

Reference Angle =20°

Angle Lies in First Quadrant.

⇒≡Reference Angle of 20°, which should lie between 0° and 360° can be evaluated by using the formula=360°n+20°, for n=0,1,2,3,4,....

So,First Reference angle of 20°=20°

Second reference angle of 20°=360°× 1+20°=380°

Third Reference angle of 20°=360°× 2+20°

       =720°+20°

       =740°

Fourth Reference angle of 20°=360°×3+20°

       =1080°+20°

       =1100°  

Archy [21]4 years ago
5 0
20, 180 - 20, 180 + 20 and 360 - 20

i.e. 20°, 160°, 200° and 340°
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Write 15 1/4% as a fraction in simplest form
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3 years ago
Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on
boyakko [2]

<u>Answer:</u>

<em>Mathew invested</em><em> $600 and $2400</em><em> in each account.</em>

<u>Solution:</u>

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest (I_1) earned in first account for one year,

\text {simple interest}=\frac{\text {pnr}}{100}

Where  

p = amount invested in first account

n = number of years  

r = rate of interest

hence, by using above equation we get (I_1) as,  

I_{1}=\frac{P \times 1 \times 3}{100} ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest (I_2) earned in second account,

I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

I = I_1+ I_2 ---- eqn 4

By substituting eqn 1 , 2, 3 in eqn 4

\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}

\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400  

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600  

Hence, Mathew invested $600 and $2400 in each account.

3 0
3 years ago
Read 2 more answers
A greeting card uses a geometric design containing 4 congruent kites. The card is 4 inches wide and 8 inches long. What is the a
Gnom [1K]

Answer: 4 sq. in

Step-by-step explanation:

From the question, the card is 8 inches long. Therefore, the length of the vertical diagonal of 1 kite + the length of the vertical diagonal of other kite = 8

Since we have been told that the kites are congruent, therefore the length of the vertical diagonal of both kites will be thesame

Therefore, 2(length of the vertical diagonal of 1 kite) = 8

Therefore, the length of the vertical diagonal of 1 kite will be= 4 inches

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Therefore, the length of the horizontal diagonal of 1 kite + the length of the horizontal diagonal of another kite =4

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So, Area of kite = pq/2

Where p and q are diagonals of kite

Area of kite = (4×2)/2

=8/2

= 4 inches square

3 0
3 years ago
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