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algol13
3 years ago
9

6^2 + x - x^2 for x=3 help me pls

Mathematics
1 answer:
Stels [109]3 years ago
4 0

Answer:

30

Step-by-step explanation:

Just insert the value of x into the equation.

x = 3 right?

6^2 + 3 - 3^2 because x = 3

36 + 3 - 9 = 39 -9 = 30

:D

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A manufacturing process produces bags of cookies. The distribution of content weights of these bags is Normal with mean 15.0 oz
NeTakaya

Answer:

100 bags

Step-by-step explanation:

S.E = σ/ √n

0.1 = 1 / √n

Square both sides

0.1² = 1² / n

0.01 = 1 / n

0.01n = 1

n = 1 / 0.01

n = 100

4 0
3 years ago
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BigorU [14]
D is the answer . . .
8 0
3 years ago
Read 2 more answers
How do i solve this system of equations
WITCHER [35]
22, i think because 3 times 3= 9, and 9 times 3 minus 5= 22

8 0
3 years ago
Read 2 more answers
MULTIPLE CHOICE
Dvinal [7]

Step 1) Multiply 2 by 3

<em>5x+6 = 2x+3x+6</em>

Step 2) Combine like terms

<em>5x+6 = 5x+6</em>

Step 3) Add 5x and 6 to both sides

Answer:

<em>0 = 0</em>

4 0
3 years ago
What is the side length of the eectagkes
dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

<u>1. 5 in and 1/3 in</u>

Here,

Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2

<u>2. 5 in and 4/3 in</u>

Here,

l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2

<u>3. 5/2 in and 4/3 in</u>

let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2

<u>4. 7/6 in and 6/7 in</u>

<u>Let</u>

l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2

<u>Hence,</u>

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

8 0
3 years ago
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