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3 years ago

11

What is the square root of 5x+ 1 = 6 ?

2 answers:

Svetlanka [38]3 years ago

6 0

Simplifies to:
2.236068
x
+
1
=
6
Let's solve your equation step-by-step.
2.236068
x
+
1
=
6
Step 1: Subtract 1 from both sides.
2.236068
x
+
1
−
1
=
6
−
1
2.236068
x
=
5
Step 2: Divide both sides by 2.236068.
2.236068
x
2.236068
=
5
2.236068
x
=
2.236068

Bond [772]3 years ago

5 0

Square root of 5x+1=6
square root each side
5x+1=6 squared
5x+1=36
subtract 1 on both sides
5x=35
divide both sides by 5
x=7

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d) $8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

$\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$ $= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

= $\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

By using

(ab)ⁿ = aⁿbⁿ

$\frac{a^{m} }{a^{n} } = a^{m-n}$

= $\frac{(4)^{3} g^{9} h^{6}k^{12} ) }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

After simplification , we get

$= 8g^{9}g^{-3} h^{6} h^{-2} k^{12} - (h^{5} k^{3} )^{5}$

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$= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

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