D.radiation that’s the right answer
In a reaction involving sodium metal and chlorine gas, the amount of sodium metal required to react with 0.950 grams of chlorine gas would be 0.62 grams
<h3>Stoichiometric calculation</h3>
From the balanced equation of the reaction:
2Na (s) + Cl2 (g) ---------> 2NaCl (s)
The mole ratio of Na to Cl2 is 2:1.
Mole of 0.950 grams of chlorine gas = 0.950/70.906
= 0.0134 moles
Equivalent mole of Na = 0.0134 x 2 = 0.0268 moles
Mass of 0.0268 moles Na = 0.0268 x 22.99
= 0.62 grams
More on stoichiometric calculations can be found here: brainly.com/question/8062886
Answer:
limiting Reactant
Explanation:
In a chemical reaction, the limiting reagent, or limiting reactant, is the substance that has been completely consumed when the chemical reaction is complete.
Answer:
Rate constant = 0.0237 M-1 s-1, Order = Second order
Explanation:
In this problem, it can be observed that as the concentration decreases, the half life increases. This means the concentration of the reactant is inversely proportional to the half life.
The order of reaction that exhibit this relationship is the second order of reaction.
In the second order of reaction, the relationship between rate constant and half life is given as;
t1/2 = 1 / k[A]o
Where;
k = rate constant
[A]o = Initial concentration
k = 1 / t1/2 [A]
Uisng the following values;
k = ?
t1/2 = 113
[A]o = 0.372M
k = 1 / (113)(0.372)
k = 1 / 42.036 = 0.0237 M-1 s-1
Answer:
-5.51 kJ/mol
Explanation:
Step 1: Calculate the heat required to heat the water.
We use the following expression.
where,
- c: specific heat capacity
- m: mass
- ΔT: change in the temperature
The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.
Step 2: Calculate the heat released by the methane
According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero
Qc + Qw = 0
Qc = -Qw = -22.0 kJ
Step 3: Calculate the molar heat of combustion of methane.
The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.