Answer:
<u>We are given:</u>
v1 = 3.2 L v2 = x L
p1 = 822 torr OR 1.08 atm p2 = 2.33 atm
t1 = t2 = 284 k
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<u>From the Ideal gas equation:</u>
PV = nRT
Since the number of moles (n), universal gas constant (R) and Temperature (T) are constant
PV = k (where k is a constant)
it can also be written as:
P1V1 = k --------------------------(1)
Similarly,
P2V2 = k (where k is the same constant as before)----------(2)
<u>Solving for V2:</u>
From (1) and (2):
P1V1 = P2V2
Replacing the variables
1.08 * 3.2 = 2.33 * x
x = (1.08 * 3.2)/2.33
x = 1.5 L (approx)
Therefore, the final volume of the solution will be 1.5L
Answer:
1 is the answer
Explanation:
The ionic formula for Lithium Oxide is Li2O . Lithium is an Alkali Metal in the first column of the periodic table. This means that lithium has 1 valence electron it readily gives away in order to seek the stability of the octet.
Answer:
6782 has 4, 26.2 has 3, 0.3491 has 4 and 55 has 2 significant figures .
The number of moles of AlBr3 = Molarity × Volume
= 0.150 × 0.3
= 0.045 moles
1 mole of AlBr3 gives 3 moles of Br- ions
That is
AlBr3 = Al3+ + 3Br-
Therefore, 0.045 moles of AlBr3 will yield 3 × 0.045 = 0.135 moles
Thus; they are 0.135 moles of bromide ions
Answe 174.0 KPA
Explanation:
0°C in 101.3 K PA pressure a sample of gas occupies 30 mL if the temperature is increased to 30°C in the entire gas sample is transferred to a 20 mL container what will be the gas pressure inside a container
PV=nRTt
so
n = PV/RT
P = 101.3 KPA
T = 0+273.2 = 273.200
V = (30/1000) L = 0.03 L
R =0.082
SO
n= (101.3 X 0.03)/(0.082 X 273.2)
= 0.14 moles
PV= nRT
N= 0,14
T = 30 + 273.2= 303.2
V= (20/1000)L =0.02L
since PV = nRT
THEN
P=nRT/V
so
P=(0.14 X 0.082 X 303.2)/0.02 =
174.0 KPA