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3 years ago

What is the pH difference of two samples if the concentration of [H+] ions is 1000-fold less in the second sample?

Chemistry

2 answers:

vodomira [7]3 years ago

7 0

Answer:

The correct answer is A, just answered it on my test!!!!!

Explanation:

snow_tiger [21]3 years ago

4 0

The correct answer is a. This is because the pH of a solution is defined as -log10(concentration of H+ ions). An inverse logarithmic scale such as this means that a solution with a lower concentration of H+ ions will have a higher pH than one with a higher concentration. Therefore we know that the pH of the second sample will be higher than the first.

Since the logarithmic scale has the base 10, a change by 1 on the scale is a consequence of multiplication/division of the H+ concentration by a factor of 10. As the scale is inverse, this means that a decrease of concentration by factor 1000 is equivalent to increasing the pH by (1000/10) = 3.

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Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)

Fynjy0 [20]

Answer:

Rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

Explanation:

According to equation 2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

⇒ $-\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}$ -----------------------------(1)

Given that the rate of disappearance of oxygen = $-\frac{d[O_{2} ]}{dt}$ = 3.64 x 10⁻³ M/s

So the rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = ?

from equation (1) we can write

$\frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]$

⇒ $\frac{d[SO_{3}] }{dt}$ = 2 x 3.64 x 10⁻³ M/s

⇒ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

7 0

3 years ago

If the reactants of a reaction are HCI and NaOH, what could be a product?

Nutka1998 [239]

Answer

HCl+NaOH=NaCl+H2O (NaCl+H20)=the product

is a double substitution reaction

so the product ,one of them will be or Nacl or Water(H2O)

6 0

1 year ago

How does salt help melt the road?

QveST [7]

Lower the melting point

Explanation:

Salts helps to melt road by lowering the melting point. It acts as an impurity and generally, impurities low the melting point of substances.

Salts are used as an antifreeze.

Water freezes at 0°C and forms ice/snow which can impede human and vehicular movement.
When salt is added, it causes the depression of the freezing point by lowering it further.
The freezing point is pegged back at -6°C.
This way it takes more low temperature to freeze the water.
The salt acts as an impurity and causes the depression of melting point and widening of the melting range.

learn more:

Matter brainly.com/question/10972073

#learnwithBrainly

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3 years ago

Read 2 more answers

How are adhesion and cohesion similar? How are they different? they both stick things together.

AnnZ [28]

Answer:

Both are forces

Explanation:

6 0