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3 years ago

What is the pH difference of two samples if the concentration of [H+] ions is 1000-fold less in the second sample?

Chemistry

2 answers:

vodomira [7]3 years ago

7 0

Answer:

The correct answer is A, just answered it on my test!!!!!

Explanation:

snow_tiger [21]3 years ago

4 0

The correct answer is a. This is because the pH of a solution is defined as -log10(concentration of H+ ions). An inverse logarithmic scale such as this means that a solution with a lower concentration of H+ ions will have a higher pH than one with a higher concentration. Therefore we know that the pH of the second sample will be higher than the first.

Since the logarithmic scale has the base 10, a change by 1 on the scale is a consequence of multiplication/division of the H+ concentration by a factor of 10. As the scale is inverse, this means that a decrease of concentration by factor 1000 is equivalent to increasing the pH by (1000/10) = 3.

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A serving of soup contains 5.0 g of fat, 20.0 g of carbohydrates, and 3.0 g of protein. Determine how many kilocalories (kcal) a

marta [7]

Answer: The amount of kilocalories contained in the given serving of soup is 0.137 kCal

Explanation:

As per the USDA:

Carbohydrates provide 4 calories per gram, protein provides 4 calories per gram, and fat provides 9 calories per gram.

We are given

Mass of fat in the soup serving = 5.0 g

Mass of carbohydrates in the soup serving = 20.0 g

Mass of protein in the soup serving = 3.0 g

Conversion factor used: 1 kCal = 1000 Cal

Applying unitary method:

For Fat:

1 gram of fat provides 9 calories

So, 5.0 gram of fat will provide = $\frac{9}{1}\times 5.0=45Cal=0.045kCal$

For Carbohydrates:

1 gram of carbohydrates provides 4 calories

So, 20.0 gram of carbohydrates will provide = $\frac{4}{1}\times 20.0=80Cal=0.080kCal$

For Proteins:

1 gram of proteins provides 4 calories

So, 3.0 gram of fat will provide = $\frac{4}{1}\times 3=12Cal=0.012kCal$

Total kilocalories per serving = [0.045 + 0.080 + 0.012] kCal = 0.137 kCal

Hence, the amount of kilocalories contained in the given serving of soup is 0.137 kCal

4 0

3 years ago

The diagrams show gases that are stored in two separate but similar containers.

Nesterboy [21]

Answer: The diagrams show gases that are stored in two separate but similar containers. If both gases are at the same temperature, which one has the greater pressure? Gas 2 because it has more particles that are colliding.

Explanation:

8 0

3 years ago

The nuclear symbol for uranium-235 should be written as

ser-zykov [4K]

Answer:

²³⁵₉₂U

Explanation:

²³⁵₉₂U

The nuclear symbol of U- 235 should be written as;

235 is the mass number of uranium. The mass number is written as the superscript before the symbol of the element.

92 is the atomic number of uranium. It is written as the subscript before the symbol of the element.

7 0

2 years ago

When 27.50 liters of oxygen gas reacts with excess hydrogen gas at STP how many grams of water is produced?

telo118 [61]

Answer: The mass of water produced is 44.28 g

Explanation:

We are given:

Volume of oxygen gas = 27.50 L

At STP conditions:

22.4 L of volume is occupied by 1 mole of a substance

27.50 L of oxygen gas will be occupied by = $\frac{1mol}{22.4L}\times 27.50L=1.23mol$

The chemical equation for the formation of water follows:

$2H_2+O_2\rightarrow 2H_2O$

By the stoichiometry of the reaction:

If 1 mole of oxygen gas produces 2 moles of water

So, 1.23 moles of oxygen gas will produce = $\frac{2}{1}\times 1.23=2.46mol$ of water

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Molar mass of water = 18 g/mol

Plugging values in equation 1:

$\text{Mass of water}=(2.46mol\times 18g/mol)=44.28g$

Hence, the mass of water produced is 44.28 g

5 0

3 years ago

As the distance between two objects increases the force of gravity between them is

stellarik [79]

The force of gravity is proportional to 1/r^2, where r is the radius (distance) between the objects.
So if the force was originally $\frac{1}{r^2}$ , doubling the distance between them would make the new force $\frac{1}{(2r)^2} = \frac{1}{4r^2} = (\frac{1}{4}) \frac{1}{r^2}$

6 0

3 years ago