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igomit [66]
3 years ago
7

Factoring with GCF worksheet algebra 1

Mathematics
2 answers:
andre [41]3 years ago
8 0
Well umgdjdebjdeveievej
Sladkaya [172]3 years ago
7 0

sorry it doesn't work like that you have to show us the problems to solve it.

-Hops

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For a sample size n = 24 and a population parameter of p = 0.4, a normal curve can be used to approximate the sampling distribut
Kipish [7]

Answer:False

Step-by-step explanation:

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2 years ago
PLEASE HELP IVE BEEN STUCK ON THIS ONE FOR QUITE A WHILE.<br>​
Oksana_A [137]
-4x + 4!
The point 0,4 means that b will be equal to 4, as it’s the starting point. From there, if you go down 4 twice you have 2, and then -4.
7 0
3 years ago
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Molodets [167]
Option four is the answer bc 8^2 is 64 and so is 4^3. so for the answer to be correct, it should say = and not ≠
5 0
2 years ago
Will rate7 you brainliest
Vilka [71]

Answer:

\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)

\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)

\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)

\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)

Now, let's compute the product.

\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}

So the correct answer is the first one.

Thank you.

7 0
3 years ago
A rectangle prism has dimensions of 1/2, 2 and 7/2 inches. How many cubes with side edges of 1 inch will fit into the prism?
uysha [10]
Dimensions of the rectangular prism: a=1/2 inches, b=2 inches, c=7/2 inchesVolumen of the rectangular prism: Vr=abcVr=(1/2 inches)(2 inches)(7/2 inches)Vr=[ (1*2*7) / (2*2) ] inches^3Vr=14/4 inches^3Vr=7/2 inches^3
Side of the cube: s=1 incheVolume of the cube: Vc=s^3Vc=(1 inche)^3Vc=1 inche^3

Number of cubes will fit into the rectangular prism: nn=Vr/Vcn=(7/2 inches^3) / (1 inche^3)n=7/2n=3.5
3.5 cubes with side lengths of 1 inche will fit into the prism
Read more on Brainly.com - brainly.com/question/9194776#readmore
5 0
3 years ago
Read 2 more answers
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