Answer:
The probability that at lest one job will be missed in 57 second is
=0.819134
Step-by-step explanation:
Poisson distribution:
A discrete random variable X having the enumerable set {0,1,2,....} as the spectrum, is said to be Poisson distribution.
for x=0,1,2...
λ is the average per unit time
Given that, a job arrives at a web server with the probability 0.03.
Here λ=0.03, t=57 second.
The probability that at lest one job will be missed in 57 second is
=P(X≥1)
=1- P(X<1)
=1- P(X=0)
=0.819134
Answer:
0-t-14
Step-by-step explanation:
Its the first one I don't want to type
This is how it is done. Let me know if you have questions...
Your answer will be (B) simply use military time and subtract them and you'll get your answer best of luck.
<u><em>Answer:</em></u>
168
<u><em>Explanation:</em></u>
<u>Before we begin, remember the following:</u>
+ve * +ve = +ve -ve * -ve = +ve
+ve * -ve = -ve -ve * +ve = +ve
<u>Now, for the given problem we have:</u>
(-4) * (6) * (-7)
<u>Let's take the first two terms:</u>
(-4) * (6)
Based on the above rules, the product will be negative
<u>Therefore, </u>
(-4) * (6) = -24
<u>Now, the expression became:</u>
(-24) * (-7)
Again, based on the above rule, the product here will be positive
<u>Therefore,</u>
(-24) * (-7) = 168
Hope this helps :)
