Answer:
6 m/s²
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 30 m/s
Time (t) = 5 s
Acceleration (a) =..?
Acceleration is defined mathematically as:
Acceleration (a) = Velocity (v) /time (t)
a = v /t
With the above formula, we can obtain the acceleration of the object as follow:
Velocity (v) = 30 m/s
Time (t) = 5 s
Acceleration (a) =..?
a= v/t
a= 30/5
a = 6 m/s²
Therefore, the acceleration of the object is 6 m/s² due East.
Answer:
Ft = 0[N]
Explanation:
To understand this problem we must perform an analysis of forces on the X axis, which coincides with the axis of forces of dogs.
In this way performing a sum of forces on the X-axis we will have (newton's third law):
From this analysis we can see that the resulting or total force is equal to zero, since there is no movement.
Answer:
The belt ramp is moving at 0.047 m/s
Explanation:
Hi!
The equation for the position of an object moving in a straight line with a constant acceleration is:
x = x0 + v0 * t + 1/2 * a * t²
where:
x = position at time "t"
x0 = initial position
v0 = initial velocity
t = time
a = acceleration
If the object moves with constant speed, then, a = 0 and x = x0 + v * t
First, let´s find the lenght of the speed ramp by calculating the distance walked by Clifford.
x = x0 + v0 * t +1/2 * a * t²
x0 = 0 placing the origin of our reference system at the begining of the ramp
v0 = 0 Clifford starts from rest
t = 64 s / 4
a = 0.37 m/s²
Then:
x = 1/2 * 0.37 m/s² * 16 s = 3.0 m
Now that we know the lenght of the speed ramp, we can calculate the speed of the ramp which is constant:
x = x0 + v * t x0 = 0
x = v * t
x/t = v
<u>3.0 m / 64 s = 0.047 m/s</u>