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4 years ago

Is cold fusion science or pseudoscience

1 answer:

kondor19780726 [428]4 years ago

5 0

The experiments that claimed to demonstrate cold fusion were found
to have been faulty by others who reviewed them. Also, nobody else
was able to reproduce the finding in other laboratories. In the world
of Science, this pretty much says that the initial claims were unfounded.

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What are the things ships tie up to at dock?

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4 years ago

Which is the best estimate for the mass of a typical lineman on a high school football team

fgiga [73]

We have that the best estimate for the mass of a typical lineman on a high school football team is

$100,000 g=100kg$

From the options

1. 100,000 g

2. 100,000 kg

3. 100,000 mg

Generally

A Typical lineman cannot be as small as

$100000mg=0.1kg=100g$

A Typical linesman cannot be as massive as

$100,000kg$ as that is unrealistic

With the Average Mass of A Typical linesman can be

$100,000 g=100kg$

In conclusion

The best estimate for the mass of a typical lineman on a high school football team is

$100,000 g=100kg$

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3 years ago

how does distance change when the amount of effort force is increasesd while the amount of work done remains the same?

nlexa [21]

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4 years ago

The mass of the Moon is 7.35 x 1022 kg, while that of Earth is 5.98 x 1024 kg. The average distance from the center of the Moon

Kryger [21]

Answer:

aaa

Explanation:

$m_e$ = Mass of the Earth = 5.98 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

$r_1$ = Distance from the center of the Moon to the center of Earth = 6371000 m

$r_2$ = Distance from the center of the earth center to sun center

$m_m$ = Mass of moon = $7.35\times 10^{22}\ kg$

M = Mass of sun = $1.989\times 10^{30}\ kg$

$F_1=G\frac{m_em_m}{r_1^2}\\\Rightarrow F_1=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 7.35\times 10^{22}}{(384000000)^2}\\\Rightarrow F_1=1.988\times 10^{20}\ N$

$F_2=G\frac{Mm_e}{r_1^2}\\\Rightarrow F_2=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 1.989\times 10^{30}}{(149.6\times 10^9+6371000+695.51\times 10^6)^2}\\\Rightarrow F_2=3.511\times 10^{22} N$