Answer:
2.11 m/s
Explanation:
Take north to be positive and south to be negative.
Average velocity = displacement / time
v = (82 m + -44 m) / (14 s + 4 s)
v = 2.11 m/s
The velocity is positive, so it is 2.11 m/s north. The magnitude of the velocity is 2.11 m/s.
If a student took seven science classes, his/her at score would be 1200.
<h3>What is a graph?</h3>
A graph is a relationship in which data is presented on the axes of cartesian coordinates. The presentation of the graph must be such that it is easy to read off the graph.
Now we can see that the graph is a plot of SAT scores versus the number of science classes that students take. In this case, the slope would tell us the score per subject of a student in the SAT.
a) The mathematical model that re[resents this graph is;
y =100x + 500
b) The slope of the graph must be obtained by the use of two points thus;
m = y2 - y1/x2 - x1
m = 600 - 500/1 - 0
m = 100
c) Using the relation;
y = mx + c
m = 100
c = 500
y = 100(7) + 500
y = 1200
Thus if a student took seven science classes, his/her at score would be 1200.
Learn more about graph:brainly.com/question/16608196
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Answer:
D
Explanation:
The color you see is the color the object reflectes. The rest of the color are absorbed by that object.
Either no forces or a balanced group of forces
(not a group of "balanced forces"; there's no such thing)
To develop the problem it is necessary to apply the kinematic equations for the description of the position, speed and acceleration.
In turn, we will resort to the application of Newton's second law.
PART A) For the first part we look for the time, in a constant acceleration, knowing the speeds and the displacement therefore we know that,

Where,
X = Desplazamiento
V = Velocity
t = Time
In this case there is no initial displacement or initial velocity, therefore

Clearing for time,



PART B) This is a question about the impulse of bodies, where we turn to Newton's second law, because:
F = ma
Where,
m=mass
a = acceleration
Acceleration can also be written as,

Then





Negative symbol is because the force is opposite of the direction of moton.
PART C) Acceleration through kinematics equation is defined as




The gravity is equal to 0.8, then the acceleration is

