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stepladder [879]
3 years ago
12

For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency

(1.2×1010 Hz ) and wavelength (0.026 m ). Recall that the Avogadro constant is 6.022×1023 mol−1.
Physics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

4.79 J

Explanation:

The energy of a single photon is given by

E=hf

where

h=6.63\cdot 10^{-34} Js is the Planck constant

f is the frequency of the photon

Here we have

f=1.2\cdot 10^{10} Hz

so the energy of one photon is

E_1=(6.63\cdot 10^{-34})(1.2\cdot 10^{10})=7.96\cdot 10^{-24} J

Here we have 1 mol of photons, which contains

N=6.022\cdot 10^{23} photons (Avogadro number). So, the total energy of this mole of photons is:

E=NE_1 = (6.022\cdot 10^{23})(7.96\cdot 10^{-24})=4.79 J

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An adiabatic nozzle has an inlet area of 1 m^2 and an outlet area of 0.25 m^2. Water enters the nozzle at a rate of 5 m^3/s and
svlad2 [7]

Answer:

v=20m/S

p=-37.5kPa

Explanation:

Hello! This exercise should be resolved in the next two steps

1. Using the continuity equation that indicates that the flow entering the nozzle must be the same as the output, remember that the flow equation consists in multiplying the area by the speed

Q=VA

for he exitt

Q=flow=5m^3/s

A=area=0.25m^2

V=Speed

solving for V

V=\frac{Q}{A} \\V=\frac{5}{0.25} =20m/s

velocity at the exit=20m/s

for entry

V=\frac{5}{1} =5m/s

2.

To find the pressure we use the Bernoulli equation that states that the flow energy is conserved.

\frac{P1}{\alpha } +\frac{v1^2}{2g} =\frac{P2} {\alpha } +\frac{v2^2}{2g}

where

P=presure

α=9.810KN/m^3 specific weight for water

V=speed

g=gravity

solving for P1

(\frac{p1}{\alpha } +\frac{V1^2-V2^2}{2g})\alpha  =p2\\(\frac{150}{9.81 } +\frac{5^2-20^2}{2(9.81)})9.81  =p2\\P2=-37.5kPa

the pressure at exit is -37.5kPa

7 0
3 years ago
How does the sun's gravity and the earth inertia keep us orbiting in the solar system
scZoUnD [109]
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Vinil7 [7]
The Answer is C. the distance light travels in a year
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3 years ago
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lions [1.4K]

It's b, because the more force an object it is given the harder it will be for it to slow down.

8 0
3 years ago
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a uniform rule balance on a knife edge at the 55cm mark when a mass of 40g is hung from the 95cm mark. find the weight of the ru
BigorU [14]

Answer:

W = 3.1 N

Explanation:

moments about any convenient point will sum to zero.

I choose summing about the knife edge mark and will assume the ruler of weight W is of uniform construction.

I will assume the ruler weight makes a positive moment

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