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stepladder [879]
4 years ago
12

For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency

(1.2×1010 Hz ) and wavelength (0.026 m ). Recall that the Avogadro constant is 6.022×1023 mol−1.
Physics
1 answer:
Elanso [62]4 years ago
4 0

Answer:

4.79 J

Explanation:

The energy of a single photon is given by

E=hf

where

h=6.63\cdot 10^{-34} Js is the Planck constant

f is the frequency of the photon

Here we have

f=1.2\cdot 10^{10} Hz

so the energy of one photon is

E_1=(6.63\cdot 10^{-34})(1.2\cdot 10^{10})=7.96\cdot 10^{-24} J

Here we have 1 mol of photons, which contains

N=6.022\cdot 10^{23} photons (Avogadro number). So, the total energy of this mole of photons is:

E=NE_1 = (6.022\cdot 10^{23})(7.96\cdot 10^{-24})=4.79 J

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Concept map for kinetic energy, work and power
Helen [10]

Kinetic energy: the energy of motion

Work: the change in kinetic energy

Power: the rate of work done

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. Mathematically, it is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

The work done an object is the amount of energy transferred; according to the energy-work theorem, it is equal to the change in kinetic energy of an object:

W=K_f - K_i

where

K_f is the  final kinetic energy

K_i is the initial kinetic energy

Finally, the power is the rate of work done per unit time. Mathematically, ti can be expressed as

P=\frac{W}{t}

where

W is the work done

t is the time elapsed

Learn more about kinetic energy, work and power:

brainly.com/question/6536722

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/7956557

#LearnwithBrainly

8 0
4 years ago
What height will the object reach? 12 points. Will give brainliest.
umka21 [38]

Answer:

12.7 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 56.7 Km/hr

Maximum height (h) =..?

First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:

Initial velocity (m/s) = 56.7 x 1000/3600

Initial velocity (m/s) = 15.75 m/s

Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:

Initial velocity (u) = 15.75 m/s

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

v = u – gt (since the ball is going against gravity)

0 = 15.75 – 9.8 × t

Rearrange

9.8 × t = 15.75

Divide both side by 9.8

t = 15.75/9.8

t = 1.61 secs.

Finally, we shall determine the maximum height as follow

h = ½gt²

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 1.61 secs.

Height (h) =..?

h = ½gt²

h = ½ × 9.8 × 1.61²

h = 4.9 x 1.61²

h = 12.7 m

Therefore, the maximum height reached by the ball is 12.7 m

3 0
3 years ago
What does Newton’s law of universal gravitation say about the distance between objects?
satela [25.4K]

It says: The bigger the distance between objects the smaller the gravity between them.

3 0
4 years ago
If the magnetic field in a traveling EM wave has a peak value of 17.9nT, what is the peak value of the electric field strength?
Doss [256]

Answer:

5.37 N/C

Explanation:

Peak value of magnetic field, Bo = 17.9 nT = 17.9 x 10^-9 T

The electromagnetic wave is produced when an oscillating electric and magnetic field interacts each other perpendicularly.

The direction of propagation of electromagnetic wave is perpendicular to both electric and magnetic field.

the relation between the electric field and magnetic field amplitudes is given by

c = \frac{E_{0}}{B_{0}}

where, c be the velocity of light, Eo be the peak value of electric field strength, Bo is the peak value of magnetic field strength.

3\times 10^{8} = \frac{E_{0}}{17.9\times 10^{-9}}}

Eo = 5.37 N/C

4 0
3 years ago
The seatbelt across your chest should have about ______ fist width of slack
OLEGan [10]
The correct answer is option (c) i.e. one

<span>The seat belt across your chest should have about one fist width of the slack. Because the seat belt across your chest is required to have minimum fist width of the slack to hold the body in place and to avoid slamming of the body against the seat belt in case of a collision at high speeds. To have one fist width of the slack, makes it a safest to wear it in case of any collision. </span>
7 0
3 years ago
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