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hichkok12 [17]
3 years ago
15

What word describes the forces acting on the car

Physics
2 answers:
bixtya [17]3 years ago
5 0
I had this and the answer is unbalanced
7nadin3 [17]3 years ago
5 0
The answer is unbalanced cause it is unbalanced
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The Coulomb force between two charges q1 and q2 at separation r in air is F. If half of the separation is filled with medium of
vodomira [7]

Answer:

The new Coulomb force is q₁q₂/9πε₀r²

Explanation

The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².

Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.

Since we have air between q₂ and q₃, the coulomb force between them is

F' = q₂q₃/4πε₀d²

= q₂(q₁/κ)/4πε₀(r/2)²

=  4q₂q₁/κ4πε₀r²

= 4/κ(q₂q₁/4πε₀r²)

= 4/9 × (q₂q₁/4πε₀r²)

= q₁q₂/9πε₀r²

So, the new Coulomb force is q₁q₂/9πε₀r²

3 0
3 years ago
What is the displacement for the couple's hiking trip? Give your answer as an ordered pair, with magnitude first, followed by a
nekit [7.7K]

Answer:

Explanation:

See the attached

7 0
3 years ago
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Four football players are running down the field at the same speed. Player 1 weighs 180 lbs and is running toward the south goal
ANTONII [103]
Player 4 ..................
3 0
3 years ago
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____ 1. A mineral is inorganic, which means that it contains
Dimas [21]

Answer:

no material that were once part of living things

8 0
3 years ago
A solution containing 10.0 g of an unknown liquid and 90.0 g water has a freezing point of -3.33 °C. Given Kf = 1.86 °C/m for wa
Fantom [35]

Answer:

62.06 g/mol

Explanation:

We are given that a solution containing 10 g of an unknown liquid and 90 g

Given mass of solute =W_B=10 g

Given mass of solvent=W_A=90 g

k_f=1.86^{\circ}C/m

Freezing point of solution =-3.33^{\circ}C

Freezing point of solvent =0^{\circ}C

Change in freezing point =Depression in freezing point

=Freezing point of solvent - freezing point of solution=0+3.33=3.33^{\circ}

\Delta T_f=\frac{W_B\times K_f\times 1000}{W_A\times M_B}

M_B=\frac{10\times 1.86\times 1000}{3.33\times 90}

M_B=62.06 g/mol

Hence, molar mass of unknown liquid is 62.06g/mol.

6 0
2 years ago
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