Answer:
 p = 1.16 10⁻¹⁴ C m     and  ΔU = 2.7 10 -11 J
Explanation:
The dipole moment of a dipole is the product of charges by distance
                         p = 2 a q
With 2a the distance between the charges and the magnitude of the charges
                         p = 1.7 10⁻⁹ 6.8 10⁻⁶
                         p = 1.16 10⁻¹⁴ C m
  
The potential energie dipole  is described by the expression
                        U = - p E cos θ
Where θ is the angle between the dipole and the electric field, the zero value of the potential energy is located for when the dipole is perpendicular to the electric field line
Orientation parallel to the field
                       θ = 0º 
                       U = 1.16 10⁻¹⁴ 1160 cos 0
                       U1 = 1.35 10⁻¹¹ J
Antiparallel orientation
                        θ = 180º 
                       cos 180 = -1
                       U2 = -1.35 10⁻¹¹ J
The difference in energy between these two configurations is the subtraction of the energies
                          ΔU = | U1 -U2 |
                          ΔU = 1.35 10-11 - (-1.35 10-11)
                          ΔU = 2.7 10 -11 J
 
        
             
        
        
        
The answer is C. Electrical;mechanical
        
                    
             
        
        
        
Answer:
Reflected
Explanation:
I do not have much context here, but reflection is what happens when the sun sets on the water. The rays hit the surface of the water and bounce off, known as refelction.
Have a nice day!
      I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
 
        
             
        
        
        
Given that,
Mass of a tribble, m = 2.5 kg
Radius, r = 1.4 m
The force on the tribble from the bucket does not exceed 10 times its weight.
To find,
The maximum tangential speed.
Solution,
The force acting on the tribble is equal to the centripetal force.
F = 10mg
The formula for the centripetal force is given by :

v is maximum tangential speed

So, the maximum tangential speed is 11.7 m/s.
 
        
             
        
        
        
Answer:
128 m
Explanation:
From the question given above, the following data were obtained:
Horizontal velocity (u) = 40 m/s
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Horizontal distance (s) =? 
Next, we shall determine the time taken for the package to get to the ground. 
This can be obtained as follow:
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =? 
h = ½gt²
50 = ½ × 9.8 × t²
50 = 4.9 × t²
Divide both side by 4.9 
t² = 50 / 4.9
t² = 10.2
Take the square root of both side 
t = √10.2
t = 3.2 s
Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:
Horizontal velocity (u) = 40 m/s
Time (t) = 3.2 s
Horizontal distance (s) =? 
s = ut 
s = 40 × 3.2
s = 128 m
Therefore, the package will land at 128 m relative to the plane